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4 years ago

[OSS.01]Which of these statements is most likely correct about Newton's law on gravity?

Physics

2 answers:

irga5000 [103]4 years ago

6 0

Answer:

It does not explain why objects exert gravitational force.

Explanation:

As per the Newton's law of gravitation he said that two objects of different masses are placed at some distance from each other then the gravitational attraction force between two masses is

(1) proportional to the product of the two masses

(2) inversely proportional to the square of the distance between two masses

so it is given by

$F = \frac{Gm_1m_2}{r^2}$

so here as per Universal law of gravitation Newton gives an experimental result about the gravitational force while the theoretical explanation why the gravitational force exist is not explained by Newton's law of gravitation

So correct answer will be

It does not explain why objects exert gravitational force.

inessss [21]4 years ago

4 0

I think the first one is the correct answer

note: are not always 100% true

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15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?

____ [38]

A pendulum is not a wave.

-- A pendulum doesn't have a 'wavelength'.

-- There's no way to define how many of its "waves" pass a point
every second.

-- Whatever you say is the speed of the pendulum, that speed
can only be true at one or two points in the pendulum's swing,
and it's different everywhere else in the swing.

-- The frequency of a pendulum depends only on the length
of the string from which it hangs.

If you take the given information and try to apply wave motion to it:

   Wave speed = (wavelength) x (frequency)

   Frequency = (speed) / (wavelength) ,

you would end up with

   Frequency = (30 meter/sec) / (0.35 meter) = 85.7 Hz

Have you ever seen anything that could be described as
a pendulum, swinging or even wiggling back and forth
85 times every second ? ! ?   That's pretty absurd.

This math is not applicable to the pendulum.

6 0

3 years ago

Derive an expression for the energy needed to launch an object from the surface of Earth to a height h above the surface.Ignorin

Sergio [31]

Answer:

Explanation:

Potential energy on the surface of the earth

= - GMm/ R

Potential at height h

= - GMm/ (R+h)

Potential difference

= GMm/ R - GMm/ (R+h)

= GMm ( 1/R - 1/ R+h )

= GMmh / R (R +h)

This will be the energy needed to launch an object from the surface of Earth to a height h above the surface.

Extra energy is needed to get the same object into orbit at height h

= Kinetic energy of the orbiting object at height h

= 1/2 x potential energy at height h

= 1/2 x GMm / ( R + h)

8 0

3 years ago

A woman climbs up a ladder in 1.37 s at 2.20 m/s. How tall is the ladder?

ArbitrLikvidat [17]

Answer:

The ladder is 3.014 m tall.

Explanation:

To solve this problem, we must use the following formula:

v = x/t

where v represents the woman’s velocity, x represents the distance she climbed (the height of the ladder), and t represents the time it took her to move this distance

If we plug in the values we are given for the problem, we get:

v = x/t

2.20 = x/1.37

To solve this equation for x (the height of the ladder), we must multiply both sides by 1.37. If we do this, we get:

x = (2.20 * 1.37)

x = 3.014 m

Therefore, the ladder is 3.014 m tall.

Hope this helps!

6 0

3 years ago

Read 2 more answers

Determine la fuerza aplicada sobre un émbolo en una prensa hidráulica si se quiere cargar una lanza de 2970kg; toma en cuenta qu

Artist 52 [7]

I’m not sure sorry I really wish I could help

4 0

3 years ago

Que unidad de medida se utiliza para expresar la capacidad o volumen de un objeto? Da un ejemplo

galina1969 [7]

Answer:

<em>Explicado a continuación</em>

Explanation:

Hay una pequeña diferencia conceptual entre la capacidad y el volumen de un objeto, a saber:

El volumen hace referencia al espacio que ocupa un objeto, mientras que la capacidad hace referencia al espacio que este contiene. Calcular el volumen de un cuerpo es medir cuánto ocupa mientras que calcular su capacidad es medir cuánto cabe en él.

En la práctica, ambos conceptos son usados indistintamente, ya que tienen unidades equivalentes.

El volumen tiene unidades de longitud al cubo, como por ejemplo:

$m^3,\ cm^3\ ,dm^3,\ pie^3\ , pulg^3$

y la capacidad se suele expresar en litros o unidades derivadas: litro, mililitro, centilitro, etc.

Como mencionamos, hay equivalencia engre los dos grupos de unidades. Entre las más conocidas están:

$1\ lt=1\ dm^3,\ 1\ m^3=1000\ lt$

5 0

3 years ago