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devlian [24]
3 years ago
12

Which of the following sequences correctly displays the energy transformation from the inside of a battery to the igniter inside

a car's engine?
A.
Chemical Energy Mechanical Energy Heat Energy
B.
Chemical Energy Electrical Energy Heat Energy
C.
Heat Energy Electrical Energy Chemical Energy
D.
Electrical Energy Chemical Energy Heat Energy
Physics
1 answer:
Nadusha1986 [10]3 years ago
4 0

The CORRECT answer is actually

B.  

Chemical Energy Electrical Energy Heat Energy

Explanation:

There are chemicals inside a battery. They produce electrical energy (you can tell this because batteries have positively-charged and negatively-charged ends). Electrical energy is then transformed into heat energy so the igniter will work.

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When comparing two circuits, you note that circuit one has twice the resistance and double the voltage of circuit two. This mean
pochemuha

This means that there is same current flow in both the circuit, or the circuit one has twice the power of circuit two.

According to ohm's law, the resistance is given as

I=V/R

Since the circuit one has twice the voltage, and resistance

I1=I2

5 0
3 years ago
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A girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.00 blocks east. What
borishaifa [10]

Answer:

13 blocks

Explanation:

The total distance the student travels is 13 blocks.

 Distance is the length of path covered during the motion of a body.

 To find distance:

 Total distance  = Number of blocks to the west + number of blocks to the north + number of blocks to the east

 Total distance  = 3blocks + 4blocks + 6blocks  = 13blocks

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3 years ago
a 25 kg object is pushed with a horizontal force of 5 N esat across a table. If the force of friction is 2 N, what is the accele
Julli [10]

Answer:

Apply Newton's second law in the moving direction.

Explanation:

\begin{aligned}F &= ma\\5N-2N &= 25kg\times a\\a & = \frac{3N}{25kg}\\&= 0.12ms^{-2}\end{aligned}

Friction force applies in the opposite direction of motion; as a restriction.

8 0
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B. Find the velocity of a rider on the ride.
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D

Explanation:

Mutiply and alagrab to subterc

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A planet exerts a gravitational force of magnitude 9e22 N on a star. If the planet were 2 times closer to the star (that is, if
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To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

Planet gravitational force

F_p = 6*10^{22}N

F_p = \frac{GMm}{R^2}

F_p = 9*10^{22}N

Distance between planet and star

r = \frac{R}{2}

Gravitational force is

F = \frac{GMm}{r^2}

Applying the new distance,

F = \frac{GMm}{(\frac{R}{2})^2}

F =  4\frac{GMm}{R^2}

Replacing with the previous force,

F = 4F_p

Replacing our values

F= 4(9*10^{22}N)

F = 36*10^{22}N

Therefore the magnitude of the force on the star due to the planet is  36*10^{22}N

5 0
3 years ago
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