Answer:
c makes sense
Explanation:
if your just sitting there looking at it melt, thats not helping
Assuming you meant a 0.7 mole sample of a gas, we can approximate this by assuming that the gas is acting ideally, and use the ideal gas law PV=nRT. Using the following values:
P = 1.2 Atm
V = 0.170 L
n = 0.7 mol
R = 0.08206 L-atm/mol-K
We can rewrite the equation as: PV/nR = T
Plug in our values:
(1.2 atm)(0.170 L)/(0.08206*0.7 moles) = approximately 3.55 Kelvin = T
Answer:
41.4 s
Explanation:
Given data
- Rate constant (k): 8.42 × 10⁻² s⁻¹ at 800 °C
- Initial concentration of A ([A]₀): 5.00 M
- Concentration of A at a time t ([A]): 0.153 M
Let's consider the following reaction of first order with respect to A.
2 A ⇒ B
We can find the time that it will take for A to decrease from 5.00 M to 0.153 M using the following expression.
![ln([A]/[A]_0)=-k.t\\ln(0.153M/5.00M)=-8.42 \times 10^{-2}s^{-1} .t\\t = 41.4 s](https://tex.z-dn.net/?f=ln%28%5BA%5D%2F%5BA%5D_0%29%3D-k.t%5C%5Cln%280.153M%2F5.00M%29%3D-8.42%20%5Ctimes%2010%5E%7B-2%7Ds%5E%7B-1%7D%20%20%20.t%5C%5Ct%20%3D%2041.4%20s)