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Gennadij [26K]
3 years ago
5

During laparoscopic surgery , carbon dioxide gas is used to expand the abdomen to help create a larger working space. If 4.80 L

of CO 2 gas at 18 °C at 785 mmHg is used, what is the final volume , in liters, of the gas at 37 degrees * C and a pressure of 745 mmHg if the amount of CO 2 does not change ?
Chemistry
1 answer:
Studentka2010 [4]3 years ago
7 0

Answer:

5.37 L

Explanation:

To solve this problem we need to use the PV=nRT equation.

First we <u>calculate the amount of CO₂</u>, using the initial given conditions for P, V and T:

  • P = 785 mmHg ⇒ 785/760 = 1.03 atm
  • V = 4.80 L
  • T = 18 °C ⇒ 18 + 273.16 = 291.16 K

1.03 atm * 4.80 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 291.16 K

We <u>solve for n</u>:

  • n = 0.207 mol

Then we use that value of n for another PV=nRT equation, where T=37 °C (310.16K) and P = 745 mmHg (0.98 atm).

  • 0.98 atm * V = 0.207 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 310.16 K

And we <u>solve for V</u>:

  • V = 5.37 L
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To solve this problem, it is important to first determine the balanced chemical equation. The balanced equation is necessary as it will provide the mole-to-mole ratio needed to convert between moles O₂ and moles H₂O.

The unbalanced equation:

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                                25 moles O₂

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