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kicyunya [14]
3 years ago
11

Which choice lists the correct order of the coefficients of each substance in the following neutralization reaction when the equ

ation is balanced correctly? H2SO4 + LiOH → Li2SO4 + H2O 1, 1, 1, 1 2, 1, 2, 1 1, 2, 1, 2 1, 2, 1, 1
Chemistry
2 answers:
inessss [21]3 years ago
3 0
I got a 4 out of 1. not 100 percent sure if this is the right answer but i put 1,2,1,2
shtirl [24]3 years ago
3 0

Answer : The order of the coefficients of each substance in the following neutralization reaction are, 1, 2, 1, 2

Explanation :

Balanced chemical reaction : It is defined as the chemical reaction in which the number of individual atoms of an element in reactant side always be equal to the number of individual atoms of an element in product side.

The given unbalanced reaction will be,

H_2SO_4+LiOH\rightarrow Li_2SO_4+H_2O

In order to balance the chemical reaction, the coefficient 2 is put before the reactant LiOH and product H_2O.

The balanced chemical reaction will be,

H_2SO_4+2LiOH\rightarrow Li_2SO_4+2H_2O

By the stoichiometry we can say that, 1 moles of H_2SO_4 react with 2 moles of LiOH to give 1 mole of Li_2SO_4 and 2 moles of H_2O as a product.

Hence, the order of the coefficients of each substance in the following neutralization reaction are, 1, 2, 1, 2

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What factors affect the dynamic state of equilibrium in a chemical reaction and how?
yanalaym [24]

Answer:

Only changes in temperature will influence the equilibrium constant K_c. The system will shift in response to certain external shocks. At the new equilibrium Q will still be equal to K_c, but the final concentrations will be different.

The question is asking for sources of the shocks that will influence the value of Q. For most reversible reactions:

  • External changes in the relative concentration of the products and reactants.

For some reversible reactions that involve gases:

  • Changes in pressure due to volume changes.

Catalysts do not influence the value of Q. See explanation.

Explanation:

\displaystyle K_c = {e}^{\Delta G/(R\cdot T)}.

Similar to the rate constant, the equilibrium constant K_c depends only on:

  • \Delta G the standard Gibbs energy change of the reaction, and
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The reversible reaction is in a dynamic equilibrium when the rate of the forward reaction is equal to the rate of the backward reaction. Reactants are constantly converted to products; products are constantly converted back to reactants. However, at equilibrium Q = K_c the two processes balance each other. The concentration of each species will stay the same.

Factors that alter the rate of one reaction more than the other will disrupt the equilibrium. These factors shall change the rate of successful collisions and hence the reaction rate.

  • Changes in concentration influence the number of particles per unit space.
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For reactions that involve gases,

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However, there are cases where the number of gases particles on the reactant side and the product side are equal. Rates of the forward and backward reaction will change by the same extent. In such cases, there will not be a change in the final concentrations. Similarly, catalysts change the two rates by the same extent and will not change the final concentrations. Adding noble gases will also change the pressure. However, concentrations stay the same and the equilibrium position will not change.

8 0
3 years ago
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Answer:

V_2=10L

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:

\frac{V_2}{T_2} =\frac{V_1}{T_1}

In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5.0L*600K}{300K}\\\\V_2=10L

Regards!

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