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3 years ago

What type of effects do prostaglandins produce on smooth muscles? List two examples.

1 answer:

3 0

First, they may produce direct and relatively short-lived effects, such as stimulation of the isolated uterus or relaxation of the isolated tracheal chain preparation.

Secondly, in doses too low to produce a direct effect, they may produce a long-term potentiation of the effects of other stimulants.

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How far is Louisville from the nearest oil field?

rjkz [21]

Answer:

anyywhere between 20-23 miles

Explanation:

it depends what type of oil field u mean

7 0

3 years ago

Read 2 more answers

25. 00 ml of a buffer solution contains 0. 500 m hclo and 0. 380 m naclo. if 50. 00 ml of water is added to the buffer, what are

geniusboy [140]

The new concentrations of $HClO$ and $NaClO$ are 0.25M and 19M

Calculation of number of moles of each component,

Molarity of $HClO$ = number of moles/volume in lit = 0. 500 M

Number of moles = molarity of $HClO$ × volume in lit = 0. 500 M× 0.025 L

Number of moles of $HClO$ = 0.0125 mole

Molarity of $NaClO$ = number of moles/volume in lit = 0. 38 M

Number of moles = molarity of $NaClO$ × volume in lit = 0. 38 M× 0.025 L

Number of moles of $NaClO$ = 0.95 mole

Calculation of new concentration at volume 50 ml ( 0.05L)

Molarity of $HClO$ = number of moles/volume in lit = 0.0125 mole/0.05L

Molarity of $HClO$ = 0.25M

Molarity of $NaClO$ = number of moles/volume in lit = 0.95mole/0.05L

Molarity of $NaClO$ = 19 M

learn about Molarity

brainly.com/question/8732513

#SPJ4

5 0

1 year ago

Which of the following is true for all chemical reactions

Zolol [24]

The answer to the question is C

5 0

3 years ago

The quantitative amount of charge separation in a diatomic molecule contributes to the dipole moment of that molecule. A. True B

SOVA2 [1]

Answer:

The answer is True.

Explanation:

The sentence above is true it all adds up.

8 0

2 years ago

Salt is often added to water to raise the boiling point to heat food more quickly. if you add 30.0g of salt to 3.75kg of water,

sammy [17]

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

<h3>What is the boiling-point elevation?</h3>

Boiling-point elevation describes the phenomenon that the boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.

Step 1: Calculate the molality of the solution.

We will use the definition of molality.

b = mass solute / molar mass solute × kg solvent

b = 30.0 g / (58.44 g/mol) × 3.75 kg = 0.137 m

Step 2: Calculate the boiling-point elevation.

We will use the following expression.

ΔT = Kb × m × i

ΔT = 0.512 °C/m × 0.137 m × 2 = 0.140 °C

where

ΔT is the boiling-point elevation
Kb is the ebullioscopic constant.
b is the molality.
i is the Van't Hoff factor (i = 2 for NaCl).

The normal boiling-point for water is 100 °C. The boiling-point of the solution will be:

100 °C + 0.140 °C = 100.14 °C

Learn more about boiling-point elevation here: brainly.com/question/4206205

7 0

2 years ago