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baherus [9]
3 years ago
10

Radioactive gold-198 is used in the diagnosis of liver problems. the half-life of this isotope is 2.7 days. if you begin with a

sample of 8.1 mg of the isotope, how much of this sample remains after 2.6 days?
Chemistry
1 answer:
Neporo4naja [7]3 years ago
6 0

Answer:

See explanation below

Explanation:

To solve this problem, we need to use the expression of half life decay of concentration (or mass) which is the following:

m = m₀e^-kt  (1)

In this case, k will be the constant rate of this element. This is calculated using the following expression:

k = ln2/t₁/₂  (2)

Let's calculate the value of k first:

k = ln2/2.7 = 0.2567 d⁻¹

Now, we can use the expression (1) to calculate the remaining mass:

m = 8.1 * e^(-0.2567 * 2.6)

m = 8.1 * e^(-0.6674)

m = 8.1 * 0.51303

m = 4.16 mg remaining

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Electron configuration of br-1
lubasha [3.4K]

Answer:

Hi myself Shrushtee

Explanation:

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5 0
2 years ago
List the number of each type of atom on the right side of the equation hbr(aq)+2naoh(aq)→2nabr(s)+h2o(l)
ser-zykov [4K]

On the basis of the given unbalanced equation, that is:

HBr (aq) + 2NaOH (aq) → 2NaBr (s) + H2O (l)

On the right side of the equation, there are 2 atoms of sodium (Na), 2 atoms of bromine (Br), 2 atoms of hydrogen (H), and 1 atom of oxygen (O₂).

After balancing the equation correctly we get:

HBr (aq) + NaOH (aq) → NaBr (s) + H2O (l)

On the right side, one atom of Na, 1 atom of Br, 1 atom of H and one atom of O₂.

5 0
3 years ago
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Which rock is an example of a clastic sedimentary rock?
Anton [14]
The correct answer is Shale
8 0
3 years ago
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Un gas ocupa 24,6 litros a 27°C y 10 moles, que presión posee. R=0.082
Anastasy [175]

Answer:

P=10 atm

Explanation:

Hola,

En este caso, usando la ecuación del gas ideal, podemos calcular facilmente la presión a partir de:

PV=nRT

Por lo que despejando para la presión obtenemos:

P=\frac{nRT}{V}

Así, calculamos:

P=\frac{10mol*0.082\frac{atm*L}{mol*K}*(27+273)K}{24.6L} \\\\P=10 atm

¡Saludos!

7 0
3 years ago
you find that 7.36g of a compound has decomposed to give 6.93g of oxygen. the only other element in the compound is hydrogen. if
slavikrds [6]
First solve the moles of oxgen present in the compound

mol O = 6.93 g O ( 1 mol O / 16 g O )
mol O = 0.43 mol H

then solve the moles of hydrogen present
mol H = ( 7.36 - 6.93) g H ( 1 mol H / 1 g H)
mol H = 0.43 mol H
so the O and H are in the same mole content so the molecular formula would be OH, but the molar mass will not satisfy. so the answer would be
H2O2

8 0
3 years ago
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