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baherus [9]
3 years ago
10

Radioactive gold-198 is used in the diagnosis of liver problems. the half-life of this isotope is 2.7 days. if you begin with a

sample of 8.1 mg of the isotope, how much of this sample remains after 2.6 days?
Chemistry
1 answer:
Neporo4naja [7]3 years ago
6 0

Answer:

See explanation below

Explanation:

To solve this problem, we need to use the expression of half life decay of concentration (or mass) which is the following:

m = m₀e^-kt  (1)

In this case, k will be the constant rate of this element. This is calculated using the following expression:

k = ln2/t₁/₂  (2)

Let's calculate the value of k first:

k = ln2/2.7 = 0.2567 d⁻¹

Now, we can use the expression (1) to calculate the remaining mass:

m = 8.1 * e^(-0.2567 * 2.6)

m = 8.1 * e^(-0.6674)

m = 8.1 * 0.51303

m = 4.16 mg remaining

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4 years ago
Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho
Zina [86]

<u>Given:</u>

Calculated density values-

Aluminum = 2.7 g/cm3

Copper = 9.0 g/cm3

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Unknown sample mass = 9.5 g

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<u>To determine:</u>

The identity of the unknown sample

<u>Explanation:</u>

'Density' is a physical parameter which can be used to identify the nature of the unknown substance.

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This matches closely with the calculated density of titanium

Ans: The unknown substance is made of titanium

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What is the density of a solid that has a mass of 9.2 grams and a volume of 12.3 cm3 ? Would this object float or sink in water?
cluponka [151]
  • Mass=9.2g
  • Volume=12.3

\boxed{\sf Density=\dfrac{Mass}{Volume}}

\\ \sf\longmapsto Density=\dfrac{9.2}{12.3}

\\ \sf\longmapsto Density=0.74g/cm^3

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7 0
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