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Vera_Pavlovna [14]
3 years ago
8

Which of the following would need resonance structures? SO2 CH4 O2 CO3-2

Chemistry
1 answer:
VikaD [51]3 years ago
6 0
The answer is CO₃²⁻
the structure of SO2 does not permit resonance, ··O≡S≡O··
CH4 is a saturated compound. Saturated compounds don't resonate.
O2 is a gas that is already in its stable form and so can't resonate.
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Shkiper50 [21]

The answer is - 4 thats the charge of Si O

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7 0
3 years ago
How does earth maintain its energy balance
Margarita [4]
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5 0
3 years ago
A sample of copper powder is heated in an evaporating dish using a Bunsen burner. If the mass of the powder in the evaporating d
Charra [1.4K]

Answer : The correct option is, (A) the copper must have combined with another substance.

Explanation :

According to the question, when a sample of copper powder is heated in an evaporating dish by using Bunsen burner then the mass of the powder in the evaporating dish increases after heating that means the copper powder will be combined with the another substance.

If the mass of powder in the evaporating dish is decreases after the heating then the copper powder must have lost some matter.

The given option C and D are wrong statements because the hot copper is less dense than the cold copper and as we know that the density is directly proportional to the mass of a substance that means the hot copper weighs less than cold copper.

Hence, the correct option is, (A) the copper must have combined with another substance.

5 0
2 years ago
The first two ionization energies of nickel.
Radda [10]
The first two ionization energy of nickel are expressed as:
Ni(g) = Ni^+(g) + e^- Ni^+(g) = Ni^2+(g) + e^- 
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Hope this helps.
7 0
3 years ago
The mass of the quartz crystal shown below is 10 grams, and its volume is 4 cm3. What is the density of quartz?
Tju [1.3M]

Answer:

{\boxed{\text{b. 2.5 g/cm}^{3}}}

Explanation:

\text{Density} = \dfrac{m}{V} = \dfrac{\text{mass}}{\text{volume}}

Data:

m = 10 g

V = 4 cm³

Calculation:

\text{Density} = \dfrac{\text{10 g}}{\text{4 cm}^{3}} = \textbf{2.5 g/cm}^{3}\\\text{The density of the crystal is ${\boxed{\textbf{2.5 g/cm}^{3}}}$}

8 0
3 years ago
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