Answer:
{f|0 ≤ f(x)}; x² - 4x + 5
Step-by-step explanation:
To find the Quadratic Equation, plug the <em>vertex</em> into the Vertex Equation FIRST, <em>y = </em><em>a</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>h</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>k</em>, where (<em>h</em><em>,</em><em> </em><em>k</em>) → (<em>2,</em><em> </em><em>1</em>)<em> </em>is the vertex, plus, -h gives you the OPPOSITE terms of what they really are, and k gives you the EXACT terms of what they really are: (x - 2)² + 1. Doing this will give you the Quadratic Equation of <em>x² - 4x + 5</em>. You understand now?
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Answer:
|x-3|-5
Step-by-step explanation:
f(x) = |x|
These lines are lines of absolute value equations. g(x) is shifted 3 units left so we subtract 3 from within the bars, and shifted down 5 units so we subtract 5 from the absolute value which leaves us with |x-3|-5
Answer:
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Step-by-step explanation:
4.5, 4, 3.5, 3, 2.5, 2 and use the pencil and ruler, love a bit of MathsWatch
