Answer:
The solubility is 0.13 g/mL
Explanation:
Step 1: Data given
Temperature = 26.0 °C =299 K
Volume = 3.00 L
The mass of the crystals, after washing and drying = 0.36 kg = 360 grams
step 2: Calculate the solubility
3.00 L of water contains 360 grams of crystals
For 1.00L of water we'll have 360 / 3 = 130 grams of crystals
This means we have 130 grams of crystals in 1 L, this gives us a solubility of 130g/L
In 1000 mL we have 130 grams crystal
in 1 mL we have 130/1000 = 0.130 grams of crystals
The solubility is 0.13 g/mL