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dimaraw [331]
3 years ago
10

A geochemist in the field takes a small sample of the crystals of mineral compound X from a rock pool lined with more crystals o

f X. He notes the temperature of the pool, 26.° C, and caps the sample carefully. Back in the lab, the geochemist dissolves the crystals in 3.00 L of distilled water. He then filters this solution and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 0.36 kg1) Using only the information above can you calculate the solubility of X in water at 26 degrees Celsius? yes or no2) If yes calculate the solubility. Round answer to 2 signifacnt digits
Chemistry
1 answer:
Anna [14]3 years ago
3 0

Answer:

The solubility is 0.13 g/mL

Explanation:

Step 1: Data given

Temperature = 26.0 °C =299 K

Volume = 3.00 L

The mass of the crystals, after washing and drying = 0.36 kg = 360 grams

step 2: Calculate the solubility

3.00 L of water contains 360 grams of crystals

For 1.00L of water we'll have 360 / 3 = 130 grams of crystals

This means we have 130 grams of crystals in 1 L, this gives us a solubility of 130g/L

In 1000 mL we have 130 grams crystal

in 1 mL we have 130/1000 = 0.130 grams of crystals

The solubility is 0.13 g/mL

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<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
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4 0
3 years ago
The chemical equation below is correctly balanced.
DIA [1.3K]

Answer:

44.8 L of O2 will react (option D)

Explanation:

Step 1: Data given

Number of moles of SO2 = 4.00 moles

STP = Pressure = 1 atm  and temperature = 273 K

Step 2: The balanced equation

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Step 3: Calculate moles of O2

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For 4.00 moles SO2 we need 4.00 / 2 = 2.00 moles O2

Step 4: Calculate volume of O2

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For 2.00 moles we have a volume of 2*22.4 = 44.8 L

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