**Answer:**

The solubility is 0.13 g/mL

**Explanation:**

Step 1: Data given

Temperature = 26.0 °C =299 K

Volume = 3.00 L

The mass of the crystals, after washing and drying = 0.36 kg = 360 grams

step 2: Calculate the solubility

3.00 L of water contains 360 grams of crystals

For 1.00L of water we'll have 360 / 3 = 130 grams of crystals

This means we have 130 grams of crystals in 1 L, this gives us a solubility of 130g/L

In 1000 mL we have 130 grams crystal

in 1 mL we have 130/1000 = 0.130 grams of crystals

The solubility is 0.13 g/mL