Answer:
3.2043 x 10²³
Explanation:
No. of Mole of lead (Pb) = 0.532 mol
No. of atoms of lead = ?
Solution:
Formula Used to calculate
no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number
Avogadro's no. = 6.023 x10²³
So,
The formula could be written as
no. of atoms of lead Pb = no. of moles x 6.023 x10²³
Put the values in above formula
no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³
no. of atoms of lead Pb = 3.2043 x 10²³
so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.
(4.99 g) / (3.65 g/mL) = 1.37 mL
The answer to your question is 1.37ml.
Answer:
2.67 mL
Explanation:
The following data were obtained from the question:
Mass of tetracycline = 2 mg
Density of tetracycline = 0.75 mg/mL
Volume of tetracycline =?
We can obtain the volume of the tetracycline that should be given to the patient by applying the following equation:
Density = mass /volume
0.75 = 2 / volume
Cross multiply
0.75 × Volume = 2
Divide both side by 0.75
Volume = 2/0.75
Volume = 2.67 mL
Therefore, the volume of the tetracycline that should be given to the patient is 2.67 mL
Muscles bones no on organs and no on skin
