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Vadim26 [7]
3 years ago
14

Which aqueous solution should form a precipitate with aqueous cu(no3)2? 1. kno3 2. cuso4 3. k2so4 4. k2s?

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
8 0
Reaction of Cu(NO₃)₂ with each salt is as follow, 

1) with KNO₃;

                  Cu(NO₃)₂  +  KNO₃   →   Cu(NO₃)₂  +  KNO₃

Both salt products are water soluble.

2) With CuSO₄;

                  Cu(NO₃)₂  +  CuSO₄   →   CuSO₄  +  Cu(NO₃)₂
Again both Salt products are water soluble.

3) With K₂SO₄;

                  Cu(NO₃)₂  +  K₂SO₄   →  CuSO₄  +  2 KNO₃
Again both salt products are water soluble.

4) With K₂S;

                  Cu(NO₃)₂  +  K₂S   →   CuS  +  2 KNO₃
In this case CuS is water insoluble, hence precipitates out.

Result:
           Option-4 is the correct answer.
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7 0
2 years ago
When a liquid is heated, the temperature stops rising at the liquid’s ____________________.
Agata [3.3K]

Hi there,

the answer to the blank is: boiling point

When a liquid is heated, the temperature stops rising at the liquid's boiling point.

Hope this is correct :)

Have a great day

5 0
3 years ago
Read 2 more answers
Convert 7.1x10^25 molecules of water to moles
ruslelena [56]

Answer:

<h2>117.94 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.1 \times  {10}^{25} }{6.02 \times  {10}^{23} }  \\  = 117.940199...

We have the final answer as

<h3>117.94 moles</h3>

Hope this helps you

8 0
2 years ago
30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr
Alenkasestr [34]

Answer: Thus concentration of Ca(OH)_2 in mol/dm^3  is 0.011 and in g/dm^3 is 0.814

Explanation:

To calculate the concentration of Ca(OH)_2, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3         1cm^3=0.001dm^3

Putting values in above equation, we get:

1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3

The concentration in g/dm^3 is 0.011mol/dm^3\times 74g/mol=0.814g/dm^3

Thus concentration of Ca(OH)_2 is 0.011mol/dm^3 and 0.814g/dm^3

4 0
3 years ago
How do plants and animals help to maintain a balance of carbon dioxide in the atmosphere
Tom [10]
Well all I know that animals take in oxygen and take out carbon dioxide and plants take in carbon dioxide and take out oxygen
3 0
2 years ago
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