Answer:

Explanation:
The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:
Chemical equation: 
Balance H and O in basic medium: 
Balance charge: 
Balanced chemical equation:

<u>Answer:</u>
<em>When we finish, the temperature would be 32.5℃</em>
<em></em>
<u>Explanation:</u>
Density of water = mass/volume
So,
Mass of water = Density × Volume


where
= Final T - Initial T
Q is the heat energy in calories
c is the specific heat capacity (for water 1.0 cal/(g℃))
m is the mass of water
plugging in the values


Final T = ∆T + Initial T
= 7.5℃ + 25℃ = 32.5℃ (Answer).
Question:
<em>What effects does the concentration of reactants have on the rate of a reaction?</em>
Answer:
<em>Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. This occurs because a higher concentration of a reactant will lead to more collisions of that reactant in a specific time period.</em>
<em>Increasing the concentration of reactants generally increases the rate of reaction because more of the reacting molecules or ions are present to form the reaction products. ... When concentrations are already high, a limit is often reached where increasing the concentration has little effect on the rate of reaction.</em>
Hope this helps, have a good day. c;
Answer:
Most common insulation materials work by slowing conductive heat flow and--to a lesser extent--convective heat flow. Radiant barriers and reflective insulation systems work by reducing radiant heat gain. To be effective, the reflective surface must face an air space.
Explanation:
To be effective, the reflective surface must face an air space.