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lianna [129]
3 years ago
6

What is the difference between kinetic and potential energy? what is the difference between kinetic and potential energy? kineti

c energy is stored energy and has the capacity to do work; potential energy is expressed through motion. kinetic energy may eventually become potential energy, but potential energy cannot become kinetic energy. kinetic energy and potential energy are synonymous; they are defined as the capacity to do work, actively putting matter into motion. kinetic energy is energy in action, while potential energy is stored energy?
Physics
2 answers:
galina1969 [7]3 years ago
8 0

Answer:

kinetic energy of an object possesses kinetic energy due to its motion or movement.the potential energy of an object is due to its position or chemical composition

Explanation:

kinetic energy...various forms are=

thermal energy

motion energy

hydroelectric energy

wind energy

electrical energy

sound energy

various forma of potential energy are...=

chemical energy

Elastic energy

nuclear energy

Gravitational energy.

9966 [12]3 years ago
6 0
Kinetic energy is energy in action and potential energy is stored energy
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Answer:

A is a solid. C is a gas. In solid an liquid the particals are touching. In C, the particals have less affect on each other because they are so far apart.

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A force of 200 N stretches a spring 30 cm. What is the spring constant of the spring? How far would this spring stretch with a f
bija089 [108]

Hooke's Law

F = k. Δx

Δx = 30 cm = 0.3 m

200 = k . 0.3

\tt k =\dfrac{200}{0.3}= 666.6

the spring stretch for 100 N:

\tt \Delta x=\dfrac{100}{666.6}=0.15=15\:cm

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3 years ago
A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a position where the electric flux
Mila [183]

Answer:

C) 2.44 × 106 N/C

Explanation:

The electric flux through a circular loop of wire is given by

\Phi = EA cos \theta

where

E is the electric field

A is the cross-sectional area

\theta is the angle between the direction of the electric field and the normal to A

The flux is maximum when \theta=0^{\circ}, so we are in this situation and therefore cos \theta =1, so we can write

\Phi = EA

Here we have:

\Phi = 7.50\cdot 10^5 N/m^2 C is the flux

d = 0.626 m is the diameter of the coil, so the radius is

r = 0.313 m

and so the area is

A=\pi r^2 = \pi (0.313 m)^2=0.308 m^2

And so, we can find the magnitude of the electric field:

E=\frac{\Phi}{A}=\frac{7.50\cdot 10^5 Nm^2/C}{0.308 m^2}=2.44\cdot 10^6 N/C

3 0
4 years ago
The spin-drier of a washing machine revolving at 900.RPM slows down uniformly to 300.RPM while making 60. revolutions. Find the
jeyben [28]
<h2>Answer:</h2>

<u>Acceleration is </u><u>-10.57 rad/s²  </u>

<u>Time is </u><u>6 seconds</u>

<h2>Explanation:</h2><h3>a) </h3>

u=900rpm= 94.248 rad/s  

v =300rpm= 31.416 rad/s  

s=60 revolutions= 377 rad  

v²= u²+ 2as  

31.416² = 94.248²+ 2 * a * 377  

a = v²-u² / 2s

a= -10.57 rad/s²  

<h3>b) </h3>

Using 1st equation of motion

v-u/a = t

Putting the values

t = (31.4 - 94.2)/-10.57

t = 6 seconds

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3 years ago
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