Transverse waves occur when a disturbance causes oscillationsperpendicular (at right angles) to the propagation (the direction of energy transfer). Longitudinal waves occur when the oscillations are parallel to the direction of propagation.
Answer:
This type of star is called the "white dwarf." When a very massive star exhausts its nuclear fuel it explodes as a supernova.
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Answer:
Final velocity is 39.2 m/s and it travels 78.4 m/s
Explanation:
The mathematical relationship between wavelength and energy transmission E = hv.
<h3>What is Wavelength and Energy transmission?</h3>
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm). The wavelength is most frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms (Å), which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation (γ).
The most fundamental aspect of global energy integration is energy transmission. With the flow of electricity produced from coal as well as from hydro, nuclear, wind, and solar energy all being transported through power networks, electric energy transmission is a significant source of energy transport.
Wavelength and frequency are connected to energy in the same way as they are to light. Greater energy is correlated with shorter wavelengths and higher frequencies. Therefore, lower energy is produced by longer wavelengths and lower frequencies. E = hv is the energy equation.
to learn more about wavelength and frequency go to - brainly.com/question/2174631
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Answer:
2.726472 s more or 1.5874 times more time is taken than 10-lb roast.
Explanation:
Given:
- The cooking time t is related the mass of food m by:
t = m^(2/3)
- Mass of roast 1 m_1 = 20 lb
- Mass of roast 2 m_2 = 10 lb
Find:
how much longer does a 20-lb roast take than a 10-lb roast?
Solution:
- Compute the times for individual roasts using the given relation:
t_1 = (20)^(2/3) = 7.36806 s
t_2 = (10)^(2/3) = 4.641588 s
- Now take a ration of t_1 to t_2, to see how many times more time is taken by massive roast:
t_1 / t_2 = (20 / 10)^(2/3)
- Compute: t_1 / t_2 = 2^(2/3) = 1.5874 s
- Hence, a 20-lb roast takes 1.5874 times more seconds than 10- lb roast.
t_2 - t_1 = 2.726472 s more
