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Dominik [7]
3 years ago
11

In the process of respiration, animals use oxygen and release ___________.

Chemistry
2 answers:
natali 33 [55]3 years ago
7 0
Carbon dioxide CO2 and produce ATP energy
anyanavicka [17]3 years ago
6 0
Carbon dioxide and ATP are produced.
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Calculate the molarity (M) if 3.35g of H3PO4 is dissolved in water to give a total volume of 200mL
lyudmila [28]

Answer:

0.171 M

Explanation:

Step 1: Given data

  • Mass of H₃PO₄ (solute): 3.35 g
  • Volume of solution (V): 200 mL

Step 2: Calculate the moles of solute

The molar mass of H₃PO₄ is 97.99 g/mol.

3.35 g × 1 mol/97.99 g = 0.0342 mol

Step 3: Convert "V" to liters

We will use the conversion factor 1 L = 1000 mL.

200 mL × 1 L/1000 mL = 0.200 L

Step 4: Calculate the molarity of the solution

We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.0342 mol/0.200 L = 0.171 M

8 0
2 years ago
C12H22O11 + 11 H2SO4 12 C + 11 H2SO4 + 11 H2O
Vladimir [108]

Answer:

B: The sulfuric acid is not consumed or react with the reactant.

4 0
2 years ago
Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.
attashe74 [19]

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
8 0
2 years ago
The research step in the process of creating a hypothesis refers to _____.
Lelechka [254]
The is the B) doing background research about the question
3 0
3 years ago
Read 2 more answers
How many moles is 3.85 x 1025 atoms of gold?
IrinaK [193]

Answer:

64.17 Moles of Au

Explanation:

(atoms and particles are the same)

3.85 x 10 ^25 x (1 mol              

                         /6.02 x 10^23)

3.85 / 6 = .64166

.6416 x 10^2 = 64.166

If you round up the answer you will get 64.17

64.17  moles of Au

4 0
2 years ago
Read 2 more answers
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