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S_A_V [24]
3 years ago
8

What’s the solution of the following system?

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0
I believe the answer is C (-2, 4).

You might be interested in
1 - 5x = -5x + 1<br> Help pls solve for x
Vilka [71]

Answer:

x can be all real numbers

Step-by-step explanation:

1 - 5x = -5x + 1

-5x+5x=1-1

0=0

4 0
3 years ago
Read 2 more answers
The domain and range is?
Molodets [167]

Answer:

In inequality notation:

Domain: -1 ≤ x ≤ 3

Range: -4 ≤ x ≤ 0

In set-builder notation:

Domain: {x | -1 ≤ x ≤ 3 }

Range: {y | -4 ≤ x ≤ 0 }

In interval notation:

Domain: [-1, 3]

Range: [-4, 0]

Step-by-step explanation:

The domain is all the x-values of a relation.

The range is all the y-values of a relation.

In this example, we have an equation of a circle.

To find the domain of a relation, think about all the x-values the relation can be. In this example, the x-values of the relation start at the -1 line and end at the 3 line. The same can be said for the range, for the y-values of the relation start at the -4 line and end at the 0 line.

But what should our notation be? There are three ways to notate domain and range.

Inequality notation is the first notation you learn when dealing with problems like these. You would use an inequality to describe the values of x and y.

In inequality notation:

Domain: -1 ≤ x ≤ 3

Range: -4 ≤ x ≤ 0

Set-builder notation is VERY similar to inequality notation except for the fact that it has brackets and the variable in question.

In set-builder notation:

Domain: {x | -1 ≤ x ≤ 3 }

Range: {y | -4 ≤ x ≤ 0 }

Interval notation is another way of identifying domain and range. It is the idea of using the number lines of the inequalities of the domain and range, just in algebriac form. Note that [ and ] represent ≤ and ≥, while ( and ) represent < and >.

In interval notation:

Domain: [-1, 3]

Range: [-4, 0]

3 0
3 years ago
The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

5 0
3 years ago
WILL GET BRAILIEST FOR CORRECT ANSWER
Alex Ar [27]

Answer:

x = ± \sqrt{20}

Step-by-step explanation:

Given

x² = 20 ( take the square root of both sides )

x = ± \sqrt{20}

which can be simplified to

x = ± 2\sqrt{5}

[ ± means plus or minus ]

5 0
3 years ago
3(-4+x)is less than -33
ololo11 [35]

Answer:

x<-7

Step-by-step explanation:

3 0
3 years ago
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