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insens350 [35]
3 years ago
5

The leaves of plants contain specialized parts that absorb energy from sunlight. Which feature would help a plant

Chemistry
2 answers:
denis-greek [22]3 years ago
8 0

Answer:

larger overall leaf size

Explanation:

Ber [7]3 years ago
6 0

Chlorophyll  pigment found in chloroplast of leaves absorbs sunlight.

The plants has a technique in which they lean towards sunlight which helps them better to compete for sunlight.

Explanation:

The leaves of the plant consist of chloroplasts in which light absorbing pigment chlorophyll is found. The chloroplast consist of thylakoid where light reaction of photosynthesis takes place.

The presence of chlorophyll a in large amount would help plant better use the sunlight this amounts to increase number of chloroplast.

Leaning towards the sunlight is feature which helps them using more sunlight.

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Explanation:

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Carbon dioxide is the other product created.
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The total pressure of a confined mixture of gases is the sum of the pressures of each of the gases in the mixture. This is known
olganol [36]

Answer:

D

Explanation:

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3 years ago
How many significant figures are in 195.01
Masja [62]

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5 0
3 years ago
Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you
Alja [10]

<u>Answer:</u> The molality of the solution is 0.11 m

<u>Explanation:</u>

We are given:

Mole fraction of methanol = 0.135

This means that 0.135 moles of methanol is present in 1 mole of a solution

Moles of ethanol = 1 - 0.135 = 0.865 moles

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of ethanol = 0.865 moles

Molar mass of ethanol = 46 g/mol

0.865mol=\frac{\text{Mass of ethanol}}{46g/mol}\\\\\text{Mass of ethanol}=(0.865mol\times 46g/mol}=39.79g

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (methanol) = 0.135 g

M_{solute} = Molar mass of solute (methanol) = 32 g/mol

W_{solvent} = Mass of solvent (ethanol) = 39.79 g

Putting values in above equation, we get:

\text{Molality of methanol}=\frac{0.135\times 1000}{32\times 39.79}\\\\\text{Molality of methanol}=0.106m\approx 0.11m

Hence, the molality of the solution is 0.11 m

6 0
3 years ago
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