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Yuliya22 [10]
3 years ago
14

What is the change in internal energy of the system (∆U) in a process in which 10 kJ of heat energy is absorbed by the system an

d 70 kJ of work is done by the system?
Physics
1 answer:
Trava [24]3 years ago
8 0

Answer:

Explanation:

According to first law of thermodynamics:

∆U= q + w

= 10kj+(-70kJ)

-60kJ

, w = + 70 kJ

(work done on the system is positive)

q = -10kJ ( heat is given out, so negative)

∆U = -10 + (+70) = +60 kJ

Thus, the internal energy of the system decreases by 60 kJ.

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A ball that has a mechanical energy of 65 J has 12 J of kinetic energy. The ball has
bulgar [2K]

Answer:

The ball has a potential energy of 53 J.

Explanation:

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A block with mass 0.470 kg sits at rest on a light but not long vertical spring that has spring constant 85.0 N/m and one end on
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That is

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K.E = 20.27 J

Where K.E = maximum elastic potential energy stored in the spring during the motion of the blocks after the collision which is 20.27J.

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