What type of Psychologist was B.F. Skinner?
1 answer:
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Answer:
The length of the string is 0.051 meters
Explanation:
It is given that,
Tension in the string, T = 240 N
Mass of the string, m = 0.086 kg
Speed of the wave, v = 12 m/s
The speed of the wave on the string is given by :
M is the mass per unit length of the string i.e. M = m/l.......(1)
So,
M = 1.67 kg/m
The length of the string can be calculated using equation (1) :
l = 0.051 m
So, the length of the string is 0.051 meters. Hence, this is the required solution.
Answer:
B = 0.135T
Explanation:
To find the magnitude of the magnetic field you use the following formula, for the torque produced by a magnetic field B in a loop:
(1)
τ: torque = 1.51*10^-5 Nm
I: current = 2.47mA = 2.47*10^-3 A
B: magnitude of the magnetic field
A: area of the loop = 4.97cm^2 = 4.97(10^-2m)^2=4.97*10^-4m^2
N: turns = 181
θ: angle between B and the magnetic dipole (same as the direction of the normal to the plane)
You replace the values of the parameters in (1). Furthermore you do B the subject of the formula: