The cylinder's acceleration is
θ
<h3>
How do you determine a cylinder's acceleration?</h3>
The cylinder's complete radius, 
, from the center marks the contact point, therefore the torque created by friction is given by 
, where is the rotating acceleration. This rotational acceleration's corresponding linear acceleration, 
, is equal to . The cylinder, which has its mass concentrated in its center, triumphs in the competition, followed by the disc and the hoop, with their respective final velocities being roughly 
. We can also see that our findings are unaffected by the cylinders' masses.
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A solution is the answer to a problem
Answer:
True, in as far as greater magnitude = greater power.
Change the places of 'acts against the motion of an object' and 'causes an object to change speed or direction'
CH4 : H2O
1 : 2
number of moles of H2O = 1.00 x 2
number of moles of H2O = 2.00mol
mass = number of moles x molar mass
mass of H2O = 2.00 x (1 + 1 + 16)
mass of H2O = 36g
