Answer:
B. 13.7 mm
Explanation:
by similarity of rectangular triangles, we have:
(1) Δ ABC and Δ AB'C'
∴ AB/AB' = AC/AC'
∴ hypotenuse (AB)² = AC² + BC².....Pythagorean theorem
⇒ AB² = (51 mm)² + (13 mm)²
⇒ AB² = 2770 mm²
⇒ AB = 52.63 mm
(2) Δ AB'C' :
∴ hypotenuse (AB')² = AC'² + B'C'²
∴ B'C' = 3.5 mm
from (1):
⇒ AB' = (AB)(AC') / AC = (52.63)(AC') / (51 mm)
⇒ AB' = 1.032AC'.......(3)
(3) in (2):
⇒ (1.032AC')² = AC'² + (3.5)²
⇒1.065AC'² = AC'² + 12.25
⇒ 0.065AC'² = 12.25
⇒ AC'² = 188.462
⇒ AC' = √188.462
⇒ AC' = 13.72 mm
Answer:
1. Atom absorbs energy from a source
2. Electron becomes unstable because it is quantized
3. Electron jumps to a higher energy level
4. Energy is released in the form of light
5. Electron falls to a lower energy level
Answer:
Here's what I get
Explanation:
1. Water
The O-H bond in water is highly polar.
It has about one-third ionic character.
The partially-positive H atoms and partially negative O atoms strongly attract each other by hydrogen bonds.
It takes a large amount of energy to separate the water molecules from each other.
Thus, the boiling point of water is relatively high (100 °C).
2. Acetone
The C=O bond in acetone is much less polar.
It is less than 20 % ionic.
The dipole-dipole attractions in acetone are much weaker than the hydrogen bonds in water.
It takes much less energy to separate the acetone molecules from each other.
Thus, even though the molar mass of acetone is more than three times that of water, the boiling point of acetone is only 56 °C.
Answer : The correct expression for equilibrium constant will be, ![K=[O_2]^5](https://tex.z-dn.net/?f=K%3D%5BO_2%5D%5E5)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,

The expression of
will be,
![K=[O_2]^5](https://tex.z-dn.net/?f=K%3D%5BO_2%5D%5E5)
Therefore, the correct expression for equilibrium constant will be, ![K=[O_2]^5](https://tex.z-dn.net/?f=K%3D%5BO_2%5D%5E5)