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kirza4 [7]
4 years ago
10

Two flat 4.0 cm 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite each

other. Between the electrodes but not near their edges, the electric field strength is 5.5 106 N/C. What is the magnitude of the charge on each electrode? (? 0 = 8.85 10-12 C2/N m2)
Physics
1 answer:
BabaBlast [244]4 years ago
8 0

Answer:

The magnitude of the charge on each electrode is 77.8 nC.

Explanation:

Given that,

Length = 4.0 cm

Distance = 2.0 mm

Electric field strength E=5.5\times10^{6}\ N/C

We need to calculate the magnitude of the charge on each electrode

Using formula of electric field

E=\dfrac{\sigma}{\epsilon_{0}}

Where, \sigma = charge density

We know that,

The charge density is

\sigma=\dfrac{Q}{A}

Put the value of charge density into the formula of electric field

E=\dfrac{Q}{A\epsilon_{0}}

Q=EA\epsilon_{0}

Put the value into the formula

Q=5.5\times10^{6}\times4.0\times4.0\times10^{-4}\times8.85\times10^{-12}

Q=77.8\times10^{-9}\ C

Q=77.8\ nC

Hence, The magnitude of the charge on each electrode is 77.8 nC.

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Three identical train cars, coupled together, are rolling east at speed v0. A fourth car traveling east at 2v0 catches up with t
Bezzdna [24]

Answer:

1v_0

Explanation:

Assuming that cars 4 and 5 have same mass so that the momentum  

P=mv where m is mass and v is velocity hence

Momentum=0+2mv+3mv=5mv

The final mass is 2m+3m=5m

From aw of conservation of momentum

5mv_0=5mv hence v=1v_o

Therefore, the speed is 1v_0

7 0
3 years ago
The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 8.9 km. Assume the
Airida [17]

Answer:

\frac{I}{I_0}=113.68

Explanation:

P = Acoustic power = 63 µW

r = Distance to the sound source = 210 m

Acoustic power

P=IA\\\Rightarrow I=\frac{P}{A}\\\Rightarrow I=\frac{63\times 10^{-6}}{4\times \pi \times 210^2}

Threshold intensity = I_0=1\times 10^{-12}\ W/m^2

Ratio

\frac{I}{I_0}=\frac{\frac{63\times 10^{-6}}{4\times \pi \times 210^2}}{1\times 10^{-12}}\\\Rightarrow \frac{I}{I_0}=113.68

Ratio of the acoustic intensity produced by the juvenile howler to the reference intensity is 113.68

6 0
3 years ago
HELP PLEASE<br>I need help on these 2 questions
Olegator [25]

I will be brief

5. There is no displacement as it didn't move

6. Time cannot go backwards so it cannot be negative

8 0
4 years ago
I will give more points <br>for this thank you I u helped<br>me ​
scZoUnD [109]

Answer:

weight = mass×gravity

  • 15×9.8
  • 147N

<h2>stay safe healthy and happy.</h2>
6 0
3 years ago
A heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h. I
Natali5045456 [20]

The power that heat pump draws when running will be 6.55 kj/kg

A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).

Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8

We have to determine the power the heat pump draws when running.

To solve this question we have to assume that the heat pump is at steady state

Let,

Q₁ = 22000 kj/kg

COP = 2.8

Since heat pump used to heat a house runs about one-third of the time.

So,

Q₁ = 3(22000) = 66000 kj/kg

We known the formula for cop of heat pump which is as follow:

COP = Q₁/ω

2.8 = 66000 / ω

ω = 66000 / 2.8

ω = 6.66 kj/kg

Hence the power that heat pump draws when running will be 6.55 kj/kg

Learn more about heat pump here :

brainly.com/question/1042914

#SPJ4

5 0
2 years ago
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