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3 years ago

What is the time feather to fall to the surface of the moon ?

Physics

1 answer:

denpristay [2]3 years ago

8 0

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Calculate the magnitude and direction of the electric field 2.0 m from a long wire that is charged uniformly at λ = 4.0 × 10-6 C

Len [333]

Answer: 71.93 *10^3 N/C

Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:

∫E*dr=Q inside/εo Q inside is given by: λ*L then,

E*2*π*r*L=λ*L/εo

E= λ/(2*π*εo*r)= 4* 10^-6/(2*3.1415*8.85*10^-12*2 )= 71.93 * 10^3 N/C

6 0

2 years ago

A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.

Svet_ta [14]

Answer: a) 0.315 (V/L)

Explanation:

From Conservation of angular momentum, we know that

L1 = L2 ,

Therefore MV L/2 = ( Irod + Ib) x W

M/4 x V x L/2 = (M (L/2)^2 + 1/3xMxL^2) x W

M/8 X VL = (ML^2/16 + ML^2 /3 )

After elimination we have,

V/8 = 19/48 x L x W

W = 48/8 x V/19L = 6/19 x V/L

Therefore W = (0.136)X V/L

6 0

2 years ago

A photon has a momentum of 5.55 x 10-27 kg-m/s. (a) What is the photon's wavelength? nm (b) To what part of the electromagnetic

Brrunno [24]

Explanation:

It is given that,

Momentum of the photon, $p=5.55\times 10^{-27}\ kg-m/s$

(a) We need to find the wavelength of this photon. It can be calculated using the concept of De-broglie wavelength.

$\lambda=\dfrac{h}{p}$

h is the Planck's constant

$\lambda=\dfrac{6.67\times 10^{-34}\ Js}{5.55\times 10^{-27}\ kg-m/s}$

$\lambda=1.2\times 10^{-7}\ m$

$\lambda=120\ nm$

(b) The wavelength lies in the group of ultraviolet rays. The wavelength of UV rays lies in between 400 nm to 10 nm.

3 0

3 years ago

It requires 0.30 kJ of work to fully drive a stake into the ground. If the average resistive force on the stake by the ground is

LenaWriter [7]

Answer:

Length of the stake will be 0.3623 m

Explanation:

We have given energy required to fully drive a stake into ground = 0.30 KJ = 300 J

Average resistive force acting on the floor is equal to F = 828 N

We have to find the length of the stake

We know that work done is given by

W = Fd, here W is work done , F is average force and d is the length of the stake

So 300 = 828×d

d = 0.3623 m

So length of the stake will be 0.3623 m

6 0

3 years ago

Why might there be a slight downslope in in the total energy instead of a flat constant?

Butoxors [25]

Because There are frictional energy losses causing a slight downslope instead of a <span>flat constant in the total energy</span>

5 0

3 years ago