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3 years ago

Which clue can be used to identify a chemical reaction as a replacement reaction?

2 answers:

4 0

"The reaction has two reactants with ions that seem to switch places" can be used to identify a chemical reaction as a replacement reaction.

myrzilka [38]3 years ago

3 0

Answer: Option (a) is the correct answer.

Explanation:

When only one element gets displaced upon chemical reaction between a compound and an element then it is known as a single replacement reaction.

For example, $Fe_{2}O_{3}(s) + 2Al(s) \rightarrow Al_{2}O_{3}(s) + 2Fe(l)$

On the other hand, when two compounds chemically react together and their ions get replaced by each other then it is known as a double replacement reaction.

For example, $AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$

Thus, we can conclude that the reaction which has two reactants with ions that seem to switch places clue can be used to identify a chemical reaction as a replacement reaction.

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A student runs up a flight of stairs which info is not needed to calculate the rate of the student is doing work against gravity

NikAS [45]

Answer:

Explanation:

Given that a student runs up a flight of stairs which info is not needed to calculate the rate of the student is doing work against gravity A the height of the flight of stairs B the length of flight of stairs C the time taken to run up the stairs D the weight of the student

The rate of doing work is known as power.

Power = work done/time

Work done = energy = mgh

Since energy = mgh

Where mg = weight

And h = height

Time = time taken to run up the stairs.

Time, weight mg and height h will be needed while the Length of the flight is therefore not needed.

The correct answer is B.

8 0

3 years ago

I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block

borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

$T = 2\pi \sqrt{\frac{m}{k} }$

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

$T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\$

Now, determine the amplitude of oscillation, A;

$E = \frac{1}{2} kA^2$

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

$E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A = \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm$

Therefore, the amplitude of the oscillation is 2.82 cm

8 0

3 years ago

A database that is flexible and easy to use was recently installed. the data is stored in rows and columns much like a spreadshe

andre [41]

The correct answer is Relational Database

7 0

3 years ago

Circuit A in a house has a voltage of 208 V and is limited by a 40.0-A circuit breaker. Circuit B is at 120.0 V and has a 20.0-A

Setler79 [48]

Given Information:

Voltage of circuit A = Va = 208 Volts

Current of circuit A = Ia = 40 Amps

Voltage of circuit B = Vb = 120 Volts

Current of circuit B = Ib = 20 Amps

Required Information:

Ratio of power = Pa/Pb = ?

Answer:

Ratio of power = Pa/Pb = 52/15

Explanation:

Power can be calculated using Ohm's law

P = VI

Where V is the voltage and I is the current flowing in the circuit.

The power delivered by circuit A is

Pa = Va*Ia

Pa = 208*40

Pa = 8320 Watts

The power delivered by circuit B is

Pb = Vb*Ib

Pb = 120*20

Pb = 2400 Watts

Therefore, the ratio of the maximum power delivered by circuit A to that delivered by circuit B is

Pa/Pb = 8320/2400

Pa/Pb = 52/15

4 0

3 years ago

The time it takes two successive crests of an ocean wave to pass a given point is called a _____.

nika2105 [10]

The answer is Period

3 0

3 years ago

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