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jekas [21]
3 years ago
13

What volume of a 6.67 M NaCl solution contains 3.12 mol NaCl

Chemistry
1 answer:
jonny [76]3 years ago
5 0
What's the big M? Molecular weight or mol?
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In a compound, chemical energy is _______________ when bonds break.
Romashka-Z-Leto [24]

Answer:

In a compound, chemical energy is _____required__________ when bonds break.

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2 years ago
Convert 121 Cal to kilowatt-hours
gulaghasi [49]

Answer:

here

Explanation:

0.000141 to kilowatt-hours. hope this helped

6 0
3 years ago
Help??
kvasek [131]

Answer:

Mass of sodium chloride decomposed = 24.54 g

Explanation:

Given data:

Mass of sodium chloride decomposed = ?

Mass of chlorine gas formed = 15 g

Solution:

Chemical equation:

2NaCl      →         2Na + Cl₂

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 15 g/ 71 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of Cl₂ with NaCl from balance chemical equation.

                    Cl₂            :              NaCl

                      1              :                2

                      0.21         :            2×0.21 = 0.42 mol

Mass of Sodium chloride decompose:

Mass = number of moles × molar mass

Mass = 0.42 mol × 58.44 g/mol

Mass = 24.54 g

4 0
3 years ago
50 Points <br> Look at the image below
Vadim26 [7]

Answer:

B-Sucrose molecules are too large to conduct electricity in once dissolved in water.

D-Salts, like NaCL, have ionic bonds and are considered to be electrolytes:when dissolved in water, salts dissociate and form ions.

Explanation:

6 0
3 years ago
Read 2 more answers
Determine the volume of atmospheric air (at 14 lb/in.^2) needed to fill your bike tires (assuming it holds 500 mL of air) to the
Fiesta28 [93]

Boyle Law says “the pressure of fixed amount of ideal gas which is at constant temperature is inversely proportional to its volume".<span>

P = 1/V

<span>Where, P is pressure of the ideal gas and V is volume of the ideal gas.</span>

<span>For two situations, this law can be added as;
P</span>₁V₁ = P₂V₂<span>

</span><span>14 lb/in² x V₁ = 70 lb/in² x 500 mL</span><span>
                 </span><span>V₁ = 2500 mL</span><span>

Hence, the needed volume of atmospheric air = 2500 mL

<span>Here, we made two </span>assumptions. They are,
1. The atmospheric air acts as ideal gas.
2. Temperature is a constant.

<span>We didn't convert the units to SI units since converting volume and pressure are products of two numbers, they will cut off. </span></span></span>

3 0
3 years ago
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