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Genrish500 [490]
4 years ago
7

An object that’s charged has more electrons than protons. An object that’s charged has fewer electrons than protons. An object t

hat’s charged has the same number of electrons and protons.
Physics
1 answer:
Levart [38]4 years ago
3 0
An element is neutral when the charged is equal to zero. This means that the number of electrons and protons are equal. When an object has a NEGATIVE charge, its electrons are more than its protons. Also, the object has a POSITIVE charge when the number of its electrons are fewer compared to the number of the protons. 
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The index of refraction of a clear plastic is listed as 1.89 in the book, but you measured the angle of incidence 63.5° and the
lakkis [162]

Answer:

<h2>index of refraction = 1.69</h2><h2>percentage error = 10.58%</h2>

Explanation:

According to Snell's law, the ratio of the sine of angle of incidence to the sine of angle of refraction is a constant for a given pair of media. The constant is known as the refractive index.

Mathematically \frac{sin i}{sin r} = n

i = angle of incidence measured = 63.5°

r = angle of refraction measured = 32°

n = refractive index

n = \frac{sin 63.5^{0} }{sin 32^{0} } \\n = \frac{0.8949}{0.5299}\\ n = 1.69

The index fraction calculated is approx. 1.69.

If the index of refraction of a clear plastic as listed in the book is 1.89 and the calculated is 1.69, the percentage error will be calculated as thus;

%error = \frac{1.89-1.69}{1.89} * 100

%error = \frac{0.2}{1.89}*100

%error  = \frac{20}{1.89}

%error  = 10.58%

6 0
3 years ago
What is the magnetic flux linkage, in units of Weber, for a coil of 360 turns and cross sectional area of 0.133 m^2 when the mag
zalisa [80]

Answer:

83.3 Wb

Explanation:

The magnetic flux linkage through the coil is given by:

N\phi = BAN sin \theta

where

B is the magnetic field strength

A is the cross sectional area

N is the number of turns in the coil

\theta is the angle between the direction of the field and the normal to the coil

In this problem:

B = 1.74 T

A = 0.133 m^2

N = 360

\theta=90^{\circ}

Therefore, the magnetic flux linkage is

N\phi = (1.74 T)(0.133 m^2)(360) sin 90^{\circ}=83.3 Wb

7 0
3 years ago
The force that contributed to the formation of planets, determines the motion of bodies in the solar system, and pulls objects t
kykrilka [37]

Answer:

The force of gravity

Explanation:

Gravity was studied, by early scientists such as Copernicus and others, Galileo was the first to ensure that planets moved according to a physical equation that depended on a force that caused celestial bodies to move and interact with each other. But years later Newton based on studies conducted deciphering what Galileo assumed, he was able to find the equation of the force of gravity in any body in the universe. This equation depends on the masses of the two interacting bodies, the distance between them and a constant, which I call universal gravitation constant.

F_{g}=G*\frac{m_{1}*m_{2}}{r^2}

Fg = gravity force [N]

G =  universal gravitation constant = 6.67*10^(-11) [N*m^2/kg^2]

m1 = mass of the 1st body [kg]

m2 = mass of the 2nd body [kg]

r = distance between the bodies [meters]

6 0
4 years ago
What are some other examples of a force acting on an object without<br> touching it?
a_sh-v [17]
An example would be gravity
8 0
3 years ago
A pendulum on earth swings with angular frequency ω. On an unknown planet, it swings with angular frequency ω/ 4. The accelerati
Afina-wow [57]

Answer:

g / 16

Explanation:

T = 2π \sqrt{\frac{l}{g} }

angular frequency ω = 2π /T

= \sqrt{\frac{g}{l} }

ω₁ /ω₂ = \sqrt{\frac{g_1}{g_2} }

Putting the values

ω₁ = ω ,     ω₂ = ω / 4

ω₁ /ω₂ = 4

4 =  \sqrt{\frac{g}{g_2} }

g₂ = g / 16

option d is correct.

6 0
3 years ago
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