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3 years ago

6

The uncertainty in position of a proton confined to the nucleus of an atom is roughly the diameter of the nucleus. If this diame

ter is d = 7.8×10−15 m, what is the uncertainty in the proton's momentum?

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

0.135E-19kgm/s

Explanation:

Using the uncertainty principle, we find

Dp = h / (4π Dx)

= (6.63×10-34Js)/4π(3.90×10-15m) = 0.135×10-19kg m/s

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What is the person’s displacement for the trip?<br><br> what is a vector quantity? give an example.

borishaifa [10]

Answer:

+ 3.0 m

Explanation:

displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m

4 0

3 years ago

When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery

Gelneren [198K]

Answer:

B. 0.51 ohms

Explanation:

Our data is as follows:

Resistor R = 20.0ohms

V1 = 12 volts

V2 = 0.300 V

We are to get the internal resistance of this battery

Now,

I = change in voltage/R

Change in voltage = v1-v2

= 12-0.300

= 11.7

Then,

I = 11.7/20

= 0.585Ri

Now

O.300 = 0.585Ri

Ri = 0.300/0.585

= 0.51 ohms

This is therefore the internal resistance of the battery.

Thank you!

6 0

3 years ago

Technician A says that a proper U-joint inspection can be done with the driveshaft in place on the vehicle. Technician B says th

Julli [10]

Answer:

TECHNICIAN B

Explanation: Drive shaft is an elongated part of the drive system made of steel of a vehicle that transmits the <em>ENGINE TORQUE to the WHEELS</em> of a vehicle. For proper inspection a technician is expected to completely remove the driveshaft to check all its compactment. It is Cylindrical and usually used for <em>REAR-WHEEL-VEHICLES</em>. Drive shafts are known by different names like propeller shaft,Cardan shaft etc it has different types which range from

<em>One-piece drive shaft ,Two-piece drive shaft to Slip-in-tube drive shaft .</em>

6 0

3 years ago

A student throws a set of keys vertically upward to his fraternity brother, who is in a window 3.60 m above. The brother's outst

Contact [7]

Answer:

$v_{i}=10.10 m/s$

Explanation:

The equation of the position is:

$y=y_{i}+v_{i}t-0.5gt^{2}$

Where:

v(i) is the initial velocity

The initial position y(i) will be zero and the final position y = 3.60 m.

So, we just need to solve this equation for v(i).

$v_{i}=\frac{y+0.5gt^{2}}{t}$

$v_{i}=\frac{3.6+0.5*9.81*1.6^{2}}{1.6}$

$v_{i}=10.10 m/s$

Therefore, the initial velocity is 10.10 m/s upwards.

I hope it helps you!

5 0

3 years ago

Can yall Please fill out them blanks i need help it's due Today.

hjlf

Answer:

tech ed class

Explanation:

4 0

3 years ago