Kinetic and Potential Energy HistoryA roller coaster train going down hill represents merely a complex case as a body is descending an inclined plane. Newton's first two laws relate force and acceleration, which are key concepts in roller coaster physics. At amusement parks, Newton's laws can be applied to every ride. These rides range from 'The Swings' to The 'Hammer'. Newton was also one of the developers of calculus which is essential to analyzing falling bodies constrained on more complex paths than inclined planes. A roller coaster rider is in an gravitational field except with the Principle of Equivalence.Potential EnergyPotential energy is the same as stored energy. The "stored" energy is held within the gravitational field. When you lift a heavy object you exert energy which later will become kinetic energy when the object is dropped. A lift motor from a roller coaster exerts potential energy when lifting the train to the top of the hill. The higher the train is lifted by the motor the more potential energy is produced; thus, forming a greater amount if kinetic energy when the train is dropped. At the top of the hills the train has a huge amount of potential energy, but it <span>has very little kinetic energy.Kinetic Energy The word "kinetic" is derived from the Greek word meaning to move, and the word "energy" is the ability to move. Thus, "kinetic energy" is the energy of motion --it's ability to do work. The faster the body moves the more kinetic energy is produced. The greater the mass and speed of an object the more kinetic energy there will be. Hope this helped:))))</span>
Answer:
(a) Length =136.58 m
(b) T=5995 N
Explanation:
for the glider in the back
T - 1900 = 700 a
for the glider in front
12000-T -1900 = 700a
add equations
12000-3800 = 1400 a
a=5.85 m/s^2
v^2 = v0^2 + 2 a x
40^2 = 2*5.85*x
Length =136.58 m
b) plug the a back into one of the previous formula
T - 1900 = 700*5.85
T=5995 N
I believe it’s 8.3 to be precise
Answer:
A. 
B. 
C. 
D. 
Explanation:
Given:
- no. of moles of oxygen in the cylinder,
- initial pressure in the cylinder,
- initial temperature of the gas in the cylinder,
<em>According to the question the final volume becomes twice of the initial volume.</em>
<u>Using ideal gas law:</u>
A.
<u>Work done by the gas during the initial isobaric expansion:</u>
C.
<u>we have the specific heat capacity of oxygen at constant pressure as:</u>
Now we apply Charles Law:
<u>Now change in internal energy:</u>
B.
<u>Now heat added to the system:</u>
D.
Since during final cooling the process is isochoric (i.e. the volume does not changes). So,
Answer:
Explanation:
Two moles of an ideal gas at 3.0 atm and 10°C are heated up to 150 °C. If the volume is held constant during this heating, what is the final pressure? a. 4.5 atm.
