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ra1l [238]
3 years ago
6

A car with s mass of 2000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The curve h

as a radius of 80 metered. What is the centripetal force on the car
Physics
2 answers:
Molodets [167]3 years ago
8 0
F=(m*V²)/r
F=centripetal force
m=mass of the object going in a circle
v=objet´s velocity
r=radius of circle of curve

m=2000 Kg
v=25 m/s
r=80  m

F=[2000 Kg*(25 m/s)²] / 80 m=15625 N

Solution: 15625 N

Alex73 [517]3 years ago
5 0

your answer would be 15,625 N

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After a laser bean passes through two thin parallel slits, thefirst completely dark fringes occur at ± 15.00with the original di
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Answer:

143 °

Explanation:

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d sinθ = λ/2

d /λ = 1/ 2 sinθ

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= 1.93

b )

For intensity of fringe at angle θ,  the relation is

I = I₀ cos²θ

I / I₀  = cos²θ/2

Given I / I₀ =0. 1

0.1 = cos²θ/2

θ/2 = 71.5

θ = 143 °

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Explain how sound travels through the air to observer
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3 0
4 years ago
6. Draw a velocity-time graph for an object originally traveling at -3 m/s. The object
faltersainse [42]

See the graph in attachment

Explanation:

In this problem we have to draw a velocity-time graph for an object travelling initially at -3 m/s, then slowing down and turning around.

In the graph, we see that the initial velocity at time t = 0 is

v_0 = -3 m/s

and it is negative, so below the x-axis.

Later, the object slows down: this means that the magnitude of its velocity increases, therefore (since the velocity is negative) the curve must go upward, approaching and reaching the x-axis (which corresponds to zero velocity).

After that, the object's velocity keep increasing, but now it is positive: this means that the object is travelling in a direction opposite to the initial direction, so it has turned around.

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4 0
3 years ago
We have an Atwood device, two blocks connect by a string strung over a pulley, but the twist this time is that both blocks are o
Zanzabum

The Acceleration of the system is 6.41 m/s².

Given,

α= 15°, m₁ = 7kg

β= 65°, m₂ = 11 kg

Let, a be the acceleration and T is the tensions at the end it's the cord.

Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,

Resultant force, m₂a=m₂g sin β -T

11a=((11) ×g sin 65°) -T  ...(i)

Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.

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7a =7g sin 15°+T  ...(ii)

Solving both the equations by adding them,

18a=11gsin 65°+7g sin 15°-T+T

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6 0
2 years ago
Two identical cows fell into a muddy hole. One fell on its side and the other fell on its feet.Which one sank furthest into the
olga_2 [115]

Answer:

The one which falls on feet.

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Larger the area less will be the pressure and less is the area larger will be the pressure.

8 0
3 years ago
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