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3 years ago

6

A car with s mass of 2000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The curve h

as a radius of 80 metered. What is the centripetal force on the car

2 answers:

Molodets [167]3 years ago

8 0

F=(m*V²)/r
F=centripetal force
m=mass of the object going in a circle
v=objet´s velocity
r=radius of circle of curve

m=2000 Kg
v=25 m/s
r=80 m

F=[2000 Kg*(25 m/s)²] / 80 m=15625 N

Solution: 15625 N

Alex73 [517]3 years ago

5 0

your answer would be 15,625 N

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svetoff [14.1K]

1)

Answer:

Part 1)

H = 30.6 m

Part 2)

t = 2.5 s

Part 3)

t = 2.5 s

Part 4)

$v_f = 24.5 m/s$

Explanation:

Part 1)

initial speed of the ball upwards

$v_i = 24.5 m/s$

so maximum height of the ball is given by

$H = \frac{v_i^2}{2g}$

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Part 2)

As we know that final speed will be zero at maximum height

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$v_f - v_i = at$

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$t = 2.5 s$

Part 3)

Since the time of ascent of ball is same as time of decent of the ball

so here ball will same time to hit the ground back

so here it is given as

t = 2.5 s

Part 4)

since the acceleration due to earth will be same during its return path as well as the time of the motion is also same

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so we have

$v_f = 24.5 m/s$

2)

Answer:

a = 9.76 m/s/s

Explanation:

As we know that the object is released from rest

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$4.88 = \frac{1}{2}a(1^2)$

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Part 2)

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Part 1)

As it took t = 2.3 s to hit the water surface

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Part 2)

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