Vi = As * h = 1000 * 30 = 30,000 cm^3 = Vol. of the ice.
Vb = (Di/Dw) * Vi = (0.9/1.0) * 30,000 = 27,000 cm^3 = Vol. below surface - Vol. of water displaced.
27,000cm^3 * 1g/cm^3 = 27,000 grams = 27 kg = Mass of water displaced.
a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J
b.) K 2 +GmM( r 11− r 21)=6.9×10 7 J
Applying Law of Energy conservation :
K 1+U 1
=K 2+U 2
⇒K 1− r 1GmM
=K 2− r 2 GmM
where M=5.0×10 23kg,r1
=> R=3.0×10 6m and m=10kg
(a) If K 1
=5.0×10 7J and r 2
=4.0×10 6 m, then the above equation leads to
K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J
(b) In this case, we require K 2
=0 and r2
=8.0×10 6m, and solve for K 1:K 1
=K 2 +GmM (r 11− r 21)=6.9×10 7 J
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There is no SI "base unit" of density.
(Any unit of mass) divided by (any unit of volume) is
a valid unit of density.
The units of density that are seen most often are
(gram per cm³) and (kgm per meter³) .
Answer:
(A). The flux is 0.336 N.m²/C
(B). The flux is zero.
Explanation:
Given that,
Length = 4.2 cm
Width = 4.0 cm
Electric field 
Area vector is perpendicular to xy plane
(A). We need to calculate the flux
Using formula of flux

Where, E = electric field
A = area
Put the value into the formula



(B). Given electric field

We need to calculate the flux
Using formula of flux

Put the value into the formula

Here, The component of k is not given
So, the flux is

Hence, (A). The flux is -0.336 N.m²/C
(B). The flux is zero.
Answer: understandable have a nice day
Explanation: