Answer:
60.9 Kelvin
Explanation: First, write out everything that you know. You are tring to find the temperature, so the temperature will be represented by x.
Pressure (P)= 4.5 atm
Volume (V)= 3L
Number of Moles (n)= ?
Gas Consant (R)= 0.0821, if the pressure is in atm, that means r is 0.0821
Temperature (T)= x
We don't have all the information we need to plug the values into the equation. We still need to know how many moles 55.0 grans of neon is.
Ne in Grams= 55
Atomic Mass of Ne= 20.1797
55/20.1797= 2.7
moles= 2.7
Now that we have all the information we need, plug everying into the equation. In case you don't know, the Ideal Gas Law Equation is PV= nRT.
(4.5)(3) = (2.7)(0.821)x
x= 60.9
Now you have your temperature! It is 60.9 in Kelvin.
Answer:
2CO 2NO → 2CO2 N2 : Balanced
6CO2 6H2O → C6H12O6 : Unbalanced
H2CO3 → H2O CO2 : Balanced
2Cu O2 → CuO : Unbalanced
Explanation:
1.) 2CO 2NO → 2CO2 N2
2 Carbon 2
4 Oxygen 4
2 Nitrogen 2
The amount of atoms of each element on each side of the equation are the same therefore the equation is balanced.
2.) 6CO2 6H2O → C6H12O6 O2
6 Carbon 6
12 Oxygen 8
12 Hydrogen 12
The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.
3.) H2CO3 → H2O CO2
2 Hydrogen 2
1 Carbon 1
3 Oxygen 3
The amount of atoms of each element is the same on both sides of the equation therefore the equation is balanced.
2Cu O2 → CuO.
2 Cu 2
2 O 1
The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.
Answer:
.........................................................
Explanation:
Answer:
c
Explanation:
the rate of a forward process must be exactly balanced by the rate of the reverse process.
Answer:
The reason is because Flagstaff is at a higher elevation than Phoenix.
Explanation:
The air is thinner at higher elevations. You can google Flagstaff's elevation compared to Phoenix but the simple answer is that air is thinner at higher elevations and some people used to 'thicker' air find it harder to breath, especially after some strenuous exercise.
