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mariarad [96]
3 years ago
6

The blades of a fan running at low speed turn at 250 rpm. When the fan is switched to high speed, the rotation rate increases un

iformly to 350 rpm in 5.75 seconds. What is the magnitude of the angular acceleration of the blades in rad/s2?
Physics
1 answer:
fgiga [73]3 years ago
8 0

Answer:

1.82 rad/s².

Explanation:

Applying,

α = (ω₂-ω₁)/t..................... Equation 1

Where α = angular acceleration of the fan blades, ω₂ = final angular velocity of the fan blades, ω₁ = initial angular velocity of the fan blades, t =  time.

Given: ω₂ = 350 rpm = (350×0.1047) rad/s = 36.645 rad/s. ω₁ = 250 rpm = (250×0.1047) rad/s = 26.175 rad/s, t = 5.75 s.

Substitute into equation 1

α = (36.645-26.175)/5.75

α = 10.47/5.75

α = 1.82 rad/s².

Hence the magnitude of the angular acceleration of the fan blades = 1.82 rad/s²

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A motorboat heads due east at 16 m/s across a river that flows due south at 9.0 m/s. a.) What is the resultant velocity of the b
alukav5142 [94]

Answer:

a)V=18.35 m/s (South -East)

b) t =7.41 m/s

c)D= 66.70 m

Explanation:

Given that

Velocity of boat in east direction = 16 m/s

Velocity of river = 9 m/s

a)The resultant velocity V

V=\sqrt{16^2+9^2}\ m/s

V=18.35 m/s (South -East)

b)

We know that

Distance = Velocity x time

Lets t time takes to cross the river

136 = 18.35 x t

t =7.41 m/s

c)

   The distance covered downstream  

We know that

Distance = Velocity x time

t= 7.41 s

D= 7.41 x 9 m

D= 66.70 m

3 0
3 years ago
The SI units for force are what?
arsen [322]

Answer:

The SI unit of force is Newton.

Explanation:

Newton is denoted by N.

Force can be defined as the pull or push which change or try to change the state of a body from motion to rest or rest to motion in a straight line.

6 0
3 years ago
A damped mass/spring system takes 14.0 s for its amplitude of the oscillator to decrease by a factor of 9. By what factor does t
fiasKO [112]

Answer:

The correct answer is "0.246".

Explanation:

Given that the amplitude is decreased by a factor of 9, then

A \rightarrow (A-\frac{A}{9} )

A \rightarrow \frac{8A}{9}

As we know,

Energy will be:

⇒  E_{1}=\frac{1}{2}KA^2

and,

⇒  E_{2}=\frac{1}{2}K(\frac{8A}{9} )^2

          =\frac{64KA^2}{162}

⇒  \Delta E=E_1-E_2

On putting the estimated values, we get

           =\frac{1}{2}KA^2-\frac{64KA^2}{162}

⇒  \frac{\Delta E}{E}=\frac{\frac{20}{162}KA^2}{\frac{1}{2}KA^2}

          =\frac{40}{162}

          =0.246

3 0
3 years ago
In an internal combustion engine, heat flow into a gas causes it to <br> .
Sunny_sXe [5.5K]

Answer:

Along path BC of the Otto cycle, heat transfer Qh into the gas occurs at constant volume, causing a further increase in pressure and temperature. This process corresponds to burning fuel in an internal combustion engine, and takes place so rapidly that the volume is nearly constant.

7 0
2 years ago
2
luda_lava [24]

Answer:

500000N/m²

5250N

Explanation:

Given parameters:

Depth(H) = 50m

Density of water  = 1000kg/m³

Acceleration of free fall  = 10m/s

Unknown:

Pressure the water exerts on the diver = ?

Solution:

Pressure is the force per unit area on a body. In fluids, pressure is the product of density, gravity and height

  Pressure in fluids  = Density x acceleration due to gravity x height

Input the variables and solve;

    Pressure in fluids  = 1000 x 10 x 50  = 500000N/m²

B.

width of window = 150mm

height of window = 70mm

Force water exerts on the window = ?

To solve this problem;

         Pressure  = \frac{Force}{Area}

Area of the window = width x height  = 150 x 10⁻³ x 70 x 10⁻³

                                                           = 1.05 x 10 ⁻²m²

Force  = pressure x area

Input the variables;

             = 500000N/m²   x  1.05 x 10 ⁻²m²

             = 5250N

4 0
3 years ago
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