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3 years ago

What is the exact time of a full earth rotation?

Physics

2 answers:

aniked [119]3 years ago

5 0

The exact time is 23 hours, 56 minutes, and 4 seconds. hope this helps hun

Nina [5.8K]3 years ago

4 0

Partyrockchickk is on the right track, but 23:56:04 is not exactly exact.
23h 56m 4.0906s is closer, but still not exact. You'll never see an 'exact'
number written anywhere. First because it doesn't work out to an exact
decimal of anything, and second because it changes ! The Good Friday
earthquake in Alaska changed it, the Fukushima earthquake changed it,
the Nepal earthquake changed it, and the daily drag of the tides changes
it by something like 0.001 second every century.

One thing's for sure: It is definitely not 24 hours.

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A 4 kg block is pulled with 4.1 N of force to the right. The block experiences 1.0 N of

Evgesh-ka [11]

Answer:

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2 years ago

You wind a small paper tube uniformly with 153 turns of thin wire to form a solenoid. The tube\'s diameter is 5.11 mm and its le

lina2011 [118]

The concept required to solve this problem is linked to inductance. This can be defined as the product between the permeability in free space by the number of turns squared by the area over the length. Recall that Inductance is defined as the opposition of a conductive element to changes in the current flowing through it. Mathematically it can be described as

$L = \frac{\mu N^2 A}{l}$

Here,

$\mu$ = Permeability at free space

N = Number of loops

A = Cross-sectional Area

l = Length

Replacing with our values we have,

$L = \frac{(4\pi *10^{-7})(153)^2(\pi (\frac{5.11*10^{-3}}{2})^2)}{2.47*10^{-2}}$

$L = 0.00002442H$

$L = 24.42\mu H$

Therefore the Inductance is $24.42\mu H$

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3 years ago

the age of Egyptian pyramid about NTT power 11 years the mankind exist for 29 years how many seconds will be men have exist if a

Zepler [3.9K]

It makes no sense how you typed this problem out.

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2 years ago

Each plate of a parallel‑plate capacitor is a square of side 4.19 cm, 4.19 cm, and the plates are separated by 0.407 mm. 0.407 m

alexandr1967 [171]

Answer:

The electric field strength inside the capacitor is 49880.77 N/C.

Explanation:

Given:

Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m

Separation between the plates (d) = 0.407 mm = $0.407\times 10^{-3}\ m$

Energy stored in the capacitor (U) = $7.87\ nJ=7.87\times 10^{-9}\ J$

Assuming the medium to be air.

So, permittivity of space (ε) = $8.854\times 10^{-12}\ F/m$

Area of the square plates is given as:

$A=a^2=(0.0419\ m)^2=1.75561\times 10^{-3}\ m^2$

Capacitance of the capacitor is given as:

$C=\dfrac{\epsilon A}{d}\\\\C=\frac{8.854\times 10^{-12}\ F/m\times 1.75561\times 10^{-3}\ m^2 }{0.407\times 10^{-3}\ m}\\\\C=3.819\times 10^{-11}\ F$