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Scorpion4ik [409]
3 years ago
15

If you start with 30.0 grams of sodium fluoride, how many grams of magnesium fluoride will be produced?

Chemistry
1 answer:
Cloud [144]3 years ago
7 0

Answer:

22.2 g of MgF₂

Explanation:

We star from the reaction:

NaF → sodium fluoride

Mg → Magnesium

2NaF  +  Mg →  MgF₂  +  2Na

2 moles of sodium fluoride react to 1 mol of Mg in order to produce 1 mol of magnesium fluoride and 2 moles of sodium.

We convert mass of the reactant to moles:

30 g . 1mol / 41.98 g = 0.715 mol

We assume that Mg is in excess

As ratio is 2:1, if we have 0.715 moles of NaF we may produce the half of moles, of MgF₂

0.715 mol /2 = 0.357 moles of MgF₂

We convert moles to mass: 0.357 mol . 62.30g /mol = 22.2 g

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Specific heat is the quantity of heat required to change the temperature of 1 gram of a substance by 1 degree Celsius. It is the amount per unit mass that is required to raise the temperature by one degree Celsius. Every substance has its own specific heat and each has its own distinct value. The units of specific heat are joules per gram-degree Celsius (J/f C) and sometimes J/Kg K may also be used.
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3 years ago
What is the percent mass oxygen in calcium carbonate (CaCo3)?
Gnoma [55]
  <span>Step 1 is to determine the mass of each part 
Mass of Ca is 40.08 g 
Mass of C is 12.01 g 
Mass of O is 16.00 x 3 = 48.00 g 
Step 2 is to determine the total mass of the compound 
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g 

Step 3 is to determine the % of each part using the following formula: 
Mass of part / total mass x 100 = 

40.08 / 100.09 x 100 = 40.04 % Ca 

12.01 / 100.09 x 100 = 12.00 % C 

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Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :) 
40.04 
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4 0
3 years ago
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Answer:

c ) protons and neutrons

Explanation:

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron). The positive charge on a proton is equal in magnitude to the negative charge on an electron.

7 0
3 years ago
How many 20.0-g ice cubes are required to absorb 47.0 kJ from a glass of water upon melting?
Sati [7]

Hello!


The number of 20-g ice cubes required to absorb 47 kJ from a glass of water upon melting is 7 icecubes


Why?


We are going to clear from the equation of the released heat, the mass of ice (m). The specific latent heat of fusion of ice is 336 kJ/kg:


Q=m*L\\ \\ m=\frac{Q}{L}=\frac{47 kJ}{336 kJ/kg}=0,1399 kg=139,88 g\\   \\ 139,88g*\frac{1 icecube}{20g}=6,99=7icecubes


So, 7 ice cubes are required to absorb that amount of heat from the glass of water.


Have a nice day!

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