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2 years ago

Physics 1

Physics

1 answer:

Degger [83]2 years ago

7 0

The emf is induced in the wire will be 1.56 ×10 ⁻³ V. The induced emf is the product of the magnetic field,velocity and length of the wire.

<h3>What is induced emf?</h3>

Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.

When the flux coupling with a conductor or coil changes, electromotive Force, or EMF, is said to be induced.

The given data in the problem is;

B is the magnitude of the magnetic field,= 5.0 ×10⁻⁵ T

V(velocity)=125 M/SEC

L(length)=25 cm=0.25 m

The maximum emf is found as;

E=VBLsin90°

E=125 × 5.0 × 10⁻⁵ ×0.25

E=1.56 ×10 ⁻³ V

Hence, the emf is induced in the wire will be 1.56 ×10 ⁻³ V

To learn more about the induced emf, refer to the link;

brainly.com/question/16764848

#SPJ1

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The voltage entering a transformer’s primary winding is 120 volts. The primary winding is wrapped around the iron core 10 times.

loris [4]

<u>Answer</u>

48 Volts

<u>Explanation</u>
The question can be solve using the turn rule of a transformer that states;

Np/Ns = Vp/Vs
Where Np ⇒ number of turns in the primary coil.
Ns ⇒number of turns in the seconndary coil
Vp ⇒ primary voltage
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Np/Ns = Vp/Vs

10/4 = 120/Vp

Vp = (120 × 4)/10

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klio [65]

Answer:

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Explanation:

<u>Horizontal Launch </u>

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

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$\displaystyle y=\frac{g.t^2}{2}$

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$\displaystyle y_2=\frac{9.8*0.5^2}{2}$

$\displaystyle y_2=1.225\ m$

The distance it falls in the second 1/4 second is:

$y_2-y_1=1.225\ m-0.30625\ m$

$y_2-y_1=0.91875\ m$

The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second

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