The mass of an object always stays the same since it is really just the amount of matter in an object so no matter the force applied, as long as the object does not lose or gain matter, the object stays the same
Answer:
The net acceleration of the boat is approximately 6.12 m/s² downwards
Explanation:
The buoyant or lifting force applied to the boat = 790 N
The mass of the boat lifted by the buoyant force = 214 kg
The force applied to a body is defined as the product of the mass and the acceleration of the body. Therefore, the buoyant force, F, acting on the boat can be presented as follows;
Fₐ = F - W
The weight of the boat = 214 × 9.81 = 2099.34 N
Therefore;
Fₐ = 790 - 2099.34 = -1309.34 N
Fₐ = Mass of the boat × The acceleration of the boat
Given that the buoyant force, Fₐ, is the net force acting on the boat, we have;
F = Mass of the boat × The net acceleration of the boat
F = -1309.34 N = 214 kg × The net acceleration of the boat
∴ The net acceleration of the boat = -1309.34 N/(214 kg) ≈ -6.12 m/s²
The net acceleration of the boat ≈ 6.12 m/s² downwards
Answer:
- Cool, dense air begins to sink downward.
- A high-pressure system forms.
- Pressure differences cause wind to blow outward.
- The skies clear, making way for pleasant weather.
Explanation:
The air near the land warms up and rises. Cool dense air sinks being heavier. This creates a pressure difference. A high pressure system forms. This difference leads to blowing of wind from High pressure to low pressure area. Eventually sky gets clear and we experience pleasant weather. Hence, the correct order to describe this is:
- Cool, dense air begins to sink downward.
- A high-pressure system forms.
- Pressure differences cause wind to blow outward.
- The skies clear, making way for pleasant weather.
Answer:
The answer is 3.0 V
Explanation:
the formula of the potential due to a non-conductive sphere with a uniform charge at a point at a distance x from the center of the sphere is equal to:
V1 = (2*π*k*ρ*(3*r^2 - x^2))/3
where
ρ = volume charge density = 100 nC/m^3
x = distance from center = 0
r = radius = 10 cm = 0.1 m
Thus:
V1 = (2*π*k*ρ*3*r^2)/3
for x = 4 cm = 0.04 m, we have:
V4 = (2*π*k*ρ*(3*r^2 - (0.04^2))/3 = (2*π*k*ρ*(3*r^2 - 0.0016))/3
The difference between both equations:
V1 - V4 = (2*π*k*ρ*3*r^2)/3 - (2*π*k*ρ*(3*r^2 - 0.0016))/3
V1 - V4 = (2*π*k*ρ*0.0016)/3 = (2*π*9x10^9*100x10^-9*0.0016)/3 = 3.02 V = 3 V
Answer:
The answer is Gravitational pull
