1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nana76 [90]
3 years ago
12

A shunting engine in a rail yard is working on a straight east-west section of line. First it travels west for 150 s with an ave

rage velocity of 4 m/s, to hook up to 10 empty freight cars. Then it pulls the cars east with an average velocity of 3 m/s for 200 s, to a loading area. Calculate the engine's final displacement.
Physics
2 answers:
Ymorist [56]3 years ago
7 0

Displacement-1

\\ \rm\longmapsto Velocity(Time)

\\ \rm\longmapsto 150(4)

\\ \rm\longmapsto 600m

Displcaement-2

\\ \rm\longmapsto 200(3)

\\ \rm\longmapsto 600m

Total displacement=600+600=1200m

irinina [24]3 years ago
7 0

<u>Displacement-1</u>

⟼Velocity(Time)

⟼150(4)

⟼600m

<u>Displcaement-2</u>

200(3)

⟼200(3)

⟼600m

Total displacement=600+600=1200m.

You might be interested in
A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne
Charra [1.4K]

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

W_x = 500 cos37

W_y = 500 sin37

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as

F = W_y = 500 sin37

F = 300 N

so it apply 300 N force along the inclined plane

5 0
3 years ago
When you take your 1900-kg car out for a spin, you go around a corner of radius 55 m with a speed of 15 m/s. The coefficient of
pentagon [3]

Answer:

7772.72N

Explanation:

When u draw your FBD, you realize you have 3 forces (ignore the force the car produces), gravity, normal force and static friction. You also realize that gravity and normal force are in our out of the page  (drawn with a frame of reference above the car). So that leaves you with static friction in the centripetal direction.

Now which direction is the static friction, assume that it is pointing inward so

Fc=Fs=mv²/r=1900*15²/55=427500/55=7772.72N

Since the car is not skidding we do not have kinetic friction so there can only be static friction. One reason we do not use μFn is because that is the formula for maximum static friction, and the problem does not state there is maximum static friction.

7 0
3 years ago
Which term describes an advantage of wind energy?
atroni [7]

The answer is "D". This is because wind is very abundant on earth...

7 0
3 years ago
Read 2 more answers
7. If the magnitude of the gravitational force of
JulijaS [17]

Newton's Third Law states that for every action there is an opposite and equal reaction:

If the gravitational force of the Earth on the Moon is F then the gravitational force of the Moon on the Earth is also F

3 0
3 years ago
If the coefficient of friction is 0.3900 and the cylinder has a radius of 2.700 m, what is the minimum angular speed of the cyli
Aleks04 [339]

Answer:

w=3.05 rad/s or 29.88rpm

Explanation:

k = coefficient of friction = 0.3900

R = radius of the cylinder = 2.7m

V = linear speed of rotation of the cylinder

w = angular speed = V/R or to rewrite V = w*R

N = normal force to cylinder

N==\frac{m(V)^{2}}{R}=m*(w)^2*R

Friction force\\Ff = k*N\\Ff= k*m*w^2*R

Gravitational force \\Fg = m*g

These must be balanced (the net force on the people will be 0) so set them equal to each other.

Fg = Ff

m*g = k*m*w^2*R

g=k*w^{2}*R

w^2 =\frac{g}{k*R}

w=\sqrt{\frac{g}{k*R}} \\w =\sqrt{\frac{9.8\frac{m}{s^{2}}}{0.3900*2.7m}}\\ w=\sqrt{9.306}=3.05 \frac{rad}{s}

There are 2*pi radians in 1 revolution so:

RPM=\frac{w}{2\pi }*60\\RPM=\frac{3.05\frac{rad}{s}}{2\pi}*60\\RPM= 0.498*60\\RPM=29.88

So you need about 30 RPM to keep people from falling out the bottom

7 0
4 years ago
Other questions:
  • Most comets come from an area called the oort cloud true or false
    6·2 answers
  • From Kepler's third law, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to From Ke
    12·1 answer
  • A 2.0 kilogram mass is located 3.0 meters above the surface of earth. what is the magnitude of earth's gravitational field stren
    9·1 answer
  • In which medium does sound travel the fastest?
    7·1 answer
  • What two quantities do you have to know to calculate the density of and object?
    9·1 answer
  • A sound wave has a frequency of 425 Hz. What is the period of this wave
    5·1 answer
  • Engineers are designing a curved section of a highway. If the radius of curvature of the curve is 173 m, at what angle should th
    5·1 answer
  • Considerando la luz como una onda, si un rayo de luz láser pasa del aire a un vidrio transparente, ¿Cuál de las siguientes carac
    9·1 answer
  • Two upwards forces act: one of 34N which is 3.5m to the left of the axle, the other is 25N and is 2.6m to the right of the axle.
    9·1 answer
  • 2. Find the electrostatic force between two protons that are 2.0 m apart. The elementary charge of
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!