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3 years ago

14

What is the displacement of the particle in the time interval 7 seconds to 8 seconds? A. 0 meters B. 1.5 meters C. 3 meters D. 7

meters

2 answers:

Dafna11 [192]3 years ago

7 0

Answer:

It's 1.5 meters

Explanation:

plato

Dmitrij [34]3 years ago

4 0

Answer: B. 1.5 meters

Explanation:

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An object with velocity 141 ft/s has a kinetic energy of 1558.71 ftâˆ™lbf, on a planet whose gravity is 31.5 ft/s2. What is its

Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

$K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \ \times \ \ \ \ 1 \ lbf\ }$

$m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm$

Therefore, the mass of the object is 5.045 lbm.

6 0

3 years ago

Our atmosphere exerts a pressure of 14.7 lb/in2. What is the force on one square foot of the earth’s surface caused by the atmos

Studentka2010 [4]

Answer:

The force on one square foot of the earth’s surface caused by the atmosphere is 101.4 kN.

Explanation:

To force is given by:

$F = P*A$ (1)

Where:

P: is the pressure = 14.7 lb/in²

A: is the area = 1 m²

By entering the above values into equation (1) we have:

$F = P*A = 14.7 \frac{lb}{in^{2}}*\frac{4.45 N}{1 lb}*\frac{1550 in^{2}}{1 m^{2}}*1 m^{2} = 101.4 kN$

Therefore, the force on one square foot of the earth’s surface caused by the atmosphere is 101.4 kN.

I hope it helps you!

3 0

3 years ago

A roller coaster needs to climb a tall hill. How tall of a hill can it climb with an initial

iren [92.7K]

Answer:

h = 11.25m

Explanation:

mgh = 1/2mv2

gh = 1/2v2

10 x h = 1/2 x 15 x 15

20 x h = 225

h = 225/20

h = 11.25m

3 0

4 years ago

A wrecking ball has a mass of 650 kg. it swings from a cable that is 21 m long. the centripetal force on the ball is 56 n. what

sweet-ann [11.9K]

The correct answer was A "1.3 m/s"

7 0

3 years ago

Read 2 more answers

Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o

Schach [20]

Explanation:

The given data is as follows.

Temperature of metal = $296^{o}C$ = (296 + 273) K

= 569 K

Density of the metal = 8.85 $g/cm^{3}$ = $8.85 \times 10^{-6} g/m^{3}$ (as $1 cm^{3} = 10^{-6} m^{3}$ )

Atomic mass = 51.40 g/mol

Vacancies = $9.19 \times 10^{23} m^{-3}$

Formula to calculate the number of atomic sites is as follows.

n = $\frac{\rho \times N_{A}}{\text{atomic weight}}$

= $\frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}$

= $1.036 \times 10^{17} atom/m^{3}$

Now, we will calculate the energy as follows.

E = $-KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})$

where, K = $8.62 \times 10^{-5}$

E = $-8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})$

= $78.46 eV/atom$

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is $78.46 eV/atom$ .

6 0

4 years ago