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2 years ago

14

What is the displacement of the particle in the time interval 7 seconds to 8 seconds? A. 0 meters B. 1.5 meters C. 3 meters D. 7

meters

2 answers:

Dafna11 [192]2 years ago

7 0

Answer:

It's 1.5 meters

Explanation:

plato

Dmitrij [34]2 years ago

4 0

Answer: B. 1.5 meters

Explanation:

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A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 w

steposvetlana [31]

Explanation:

a) The height of the ball h with respect to the reference line is

$h = L - L\cos{31°} = L(1 - \cos{31°})$

so its initial gravitational potential energy $U_0$ is

$U = mgh = mgL(1 - \cos{31°})$

$\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})$

$\:\:\:\:\:=0.23\:\text{J}$

b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

$\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U$

We know that the initial kinetic energy $K_0,$ as well as its final gravitational potential energy $U$ are zero so we can write the conservation law as

$mgL(1 - \cos{31°}) = \frac{1}{2}mv^2$

Note that the mass gets cancelled out and then we solve for the velocity v as

$v = \sqrt{2gL(1 - \cos{31°})}$

$\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}$

$\:\:\:\:\:= 1.3\:\text{m/s}$

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3 years ago

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What does ice, liquid water and water vapor all <br> have in common?

NikAS [45]

They all included water.

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use the distributive property to express 16+48. please explain if you can or work it out so I can see how you got your answer. t

Rom4ik [11]

(40+10)+(8+6)
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3 years ago

In a collision that is not perfectly elastic, what happens to the mechanical energy of the system?

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C.

Thanks me later, that's my answer.

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3 years ago

At height h above the surface of Earth, the gravitational acceleration is What is h? Note: The radius of Earth is 6380 km.

rusak2 [61]

The acceleration of gravity is inversely proportional to
the square of the distance from Earth's center.

The acceleration of gravity is 9.8 m/s² on the Earth's surface ...
6380 km from the center.

If the acceleration of gravity at 'h' is 4.9 m/s² ... 1/2 of what it is
on the surface, then the distance from the center is

(6380 x √2) = 9,023 km (rounded) ,

and 'h' is the distance above the surface

= (9,023 - 6,380) = 2,643 km (rounded) .

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3 years ago