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3 years ago

14

What is the displacement of the particle in the time interval 7 seconds to 8 seconds? A. 0 meters B. 1.5 meters C. 3 meters D. 7

meters

2 answers:

Dafna11 [192]3 years ago

7 0

Answer:

It's 1.5 meters

Explanation:

plato

Dmitrij [34]3 years ago

4 0

Answer: B. 1.5 meters

Explanation:

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Which type of electromagnetic wave has the greatest wavelength?

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Radio waves are the longest

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What is the energy due to compressing a spring

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A superhero swings a magic hammer over her head in a horizontal plane. The end of the hammer moves around a circular path of rad

Korolek [52]

Answer:

9.21954 m/s

54 m/s²

Angle is zero

Explanation:

r = Radius of arm = 1.5 m

$\omega$ = Angular velocity = 6 rad/s

The horizontal component of speed is given by

$v_h=\omega r\\\Rightarrow v_h=6\times 1.5\\\Rightarrow v_h=9\ m/s$

The vertical component of speed is given by

$v_v=2\ m/s$

The resultant of the two components will give us the velocity of hammer with respect to the ground

$v=\sqrt{v_h^2+v_v^2}\\\Rightarrow v=\sqrt{9^2+2^2}\\\Rightarrow v=9.21954\ m/s$

The velocity of hammer relative to the ground is 9.21954 m/s

Acceleration in the vertical component is zero

Net acceleration is given by

$a_n=a_h=\omega^2r\\\Rightarrow a_n=6^2\times 1.5\\\Rightarrow a_n=54\ m/s^2$

Net acceleration is 54 m/s²

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3 years ago

Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne

VLD [36.1K]

Answer:

The the maximum emf is $2.52\times10^{-11}\ V$

Explanation:

Given that,

Magnetic field $B = 1.40\times10^{-3}\ T$

Frequency = 60 Hz

Diameter = 7.8 μm

We need to calculate the maximum emf

Using formula of emf

$\epsilon=NBA\omega$

Where, N = number of turns

B= magnetic field

A = area

Put the value in to the formula

$\epsilon=1\times1.40\times10^{-3}\times\pi\times(\dfrac{7.8\times10^{-6}}{2})^2\times2\times\pi\times60$

$\epsilon=2.52\times10^{-11}\ V$

Hence, The the maximum emf is $2.52\times10^{-11}\ V$

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