Answer:
1.2 mi/hr/sec
Explanation:
<em>a = Vf - Vi / t (formula)</em>
-----------------------------------
6mi/hr - 0 mi/hr 6 mi/hr
a = ____________ = _______ = 1.2 mi/hr/sec
5 sec 5 sec
If the ball does not have a propeller or jet engine on it, then it is an object
in free fall. That means its downward speed grows by 9.8 m/s for every
second that it's in the air.
If it happens to be traveling upward at the moment, then that won't last long.
Its upward speed is decreasing by 9.8 m/s every second. It will eventually
run out of upward gas and start moving downward. At that instant, you might
say that the direction of its velocity has changed by 180 degrees.
This problem can be solved using a kinematic equation. For this case, the following equation is useful:
v_final = v_initial + at
where,
v_final = final velocity of the nail
v_initial = initial velocity of the nail
a = acceleration due to gravity = 9.8 m/s^2
t = time
First, we determine the time it takes for the nail to hit the ground. We know that the initial velocity is 0 m/s since the nail was only dropped. It has a final velocity of 26 m/s. We substitute these values to the equation and solve for t:
26 = 0 + 9.8*t
t = 26/9.8 = 2.6531 s
The problem asks the velocity of the nail at t = 1 second. We then subtract 1 second from the total time 2.6531 with v_final as unknown.
v_final = 0 + 9.8(2.6531-1) = 16.2004 m/s.
Thus, the nail was traveling at a speed of 16. 2004 m/s, 1 second before it hit the ground.
Answer:
A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Explanation:
I'm not sure, but I would go for the more than A since its orbital speed is at its fastest and the sweep occurs in about the same period of days.
