Explanation:
The electric field of an isolated charged parallel-plate capacitor is given by :
........(1)
Where
q is the electric charge
A is the area of cross section of parallel plate
It is clear from equation (1) that the electric field of a parallel plate capacitor is directly proportional to the charge on the plate and inversely proportional to the area of cross section of a plate.
So, the correct option is (E) i.e. "none of the above".
In linear motion , when a body moves with uniform velocity , in time t , its linear displacement will be ;
S = r∅ S = vt
r∅ = vt
r.∅ / t = v
As
v = rw
where ∅ = 90° is the angle between between radius vector r and angular velocity w (omega )
In case ∅ ≠ 90° , we can write v = r w sin∅
It gives us v = w× r
<span>The side of the worm that faces up when placed in the
tray for dissection is the smoother side.
</span>You can observe the organs of these tiny creatures by dissecting a preserved earthworm<span>. In dissecting
a worm, </span><span>lay the worm on your </span>dissecting
tray<span> <span>with its dorsal side facing up.</span></span>
The answer would be B. This is because all planets in our galaxy orbit the sun.
