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Sav [38]
4 years ago
15

A heavy anvil is suspended by a 0.75 m long steel wire that has a mass of 12 g. When the wire is plucked, it hums at its fundame

ntal frequency of 120 Hz. What is the mass of the anvil?
Physics
1 answer:
Dima020 [189]4 years ago
6 0

Explanation:

It is given that,

length of steel wire, l = 0.75 m

Mass of the wire, m = 12 g = 0.012 kg

Fundamental frequency, f = 120 Hz

We need to find the mass of the anvil (m'). The fundamental frequency is given by :

f=\dfrac{v}{2l}

v is the speed of the mass

Speed is given by :

v=\sqrt{\dfrac{T}{\mu}}

\mu is the mass per unit length,\mu=\dfrac{m}{l}

f=\dfrac{1}{2l}\sqrt{\dfrac{T}{\mu}}

T is the tension in the wire,

f=\dfrac{1}{2l}\sqrt{\dfrac{Tl}{m}}

T=4f^2lm

T=4(120)^2\times 0.75\times 0.012

T = 518.4 N

Tension in the wire, T = m' g

m'=\dfrac{T}{g}

m'=\dfrac{518.4}{9.8}

m' = 52.89 kg

So, the mass of the anvil is 52.89 kg. Hence, this is the required solution.

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In an experiment, a large number of electrons are fired at a sample of neutral hydrogen atoms and observations are made of how t
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Answer:

N = 1036 times

Explanation:

The radial probability density of the hydrogen ground state is given by:

p(r) = \frac{4r^{2} }{a_{0} ^{3} } e^{\frac{-2r}{a_{0} } }

p(\frac{a_{0} }{2} ) = \frac{4(\frac{a_{0} }{2} )^{2} }{a_{0} ^{3} } e^{\frac{-2(\frac{a_{0} }{2} )}{a_{0} } }

p(2a_{0} ) = \frac{4(2a_{0}) ^{2} }{a_{0} ^{3} } e^{\frac{-4a_{0} }{a_{0} } }

N = 1300\frac{p(2a_{0}) }{p(\frac{a_{0} }{2} )}

N = 1300\frac{(2a_{0}) ^{2}e^{\frac{-4a_{0} }{a_{0} } }  }{(\frac{a_{0} }{2} )^{2} e^{\frac{-a_{0} }{a_{0} } }}

N = 1300(16) e^{-3}

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3 years ago
To win the game, a placekicker must kick a football from a point 44 m (48.1184 yd) from the goal, and the ball must clear the cr
Ganezh [65]

Answer:

The distance by the ball clear the crossbar is 1.15 m

Explanation:

Given that,

Distance = 44 m

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Angle = 31°

Height = 3.05 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

u_{x}=u\cos\theta

Put the value into the formula

u_{x}=24\cos(31)

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We need to calculate the vertical velocity

Using formula of vertical velocity

u_{y}=u\sin\theta

Put the value into the formula

u_{y}=24\sin(31)

u_{y}=12.3\ m/s

We need to calculate the time

Using formula of time

t=\dfrac{d}{u_{x}}

Put the value into the formula

t=\dfrac{44}{20.5}

t=2.1\ sec

We need to calculate the vertical height

Using equation of motion

h=u_{y}t+\dfrac{1}{2}at^2

Put the value into the formula

h=12.3\times2.1-\dfrac{1}{2}\times9.8\times(2.1)^2

h=4.2\ m

We need to calculate the distance by the ball clear the crossbar

Using formula for vertical distance

d=h-3.05

Put the value of h

d=4.2-3.05

d=1.15\ m

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What was birta system​
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The act of distributing land to an individual as salary, donation, present or reward is called birta. There was the Birta system during the Malla, Shah and Rana rule in the country.

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Act: (a) "Birta land" means any kind of land obtained or possessed in such a way that the land is wholly exempt from the State Land Tax, or that the tax payable thereon is less than the tax imposed on Raikar land of similar type in the same place, and this term also includes any land as defined in Clauses

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