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goblinko [34]
3 years ago
9

What is the work energy transfer equation?

Physics
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)

Andru [333]3 years ago
5 0

Answer:

The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)

Explanation:

The net work done on a particle equals the change in the particle's kinetic energy:

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A proton is moved from the negative to the positive plate of a parallel-plate arrangement. The plates are 1.50 cm apart, and the
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(a) The proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

(b) The potential difference between the negative plate and a point midway between the plates is 11.25 V.

(c) The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

<h3>Potential energy of the proton</h3>

U = qΔV

where;

  • q is charge of the proton
  • ΔV is potential difference

U = q(Ed)

U = (1.6 x 10⁻¹⁹)(1500 x 1.5 x 10⁻²)

U = 3.6 x 10⁻¹⁸ J

<h3>Potential difference between the negative plate and a point midway</h3>

ΔV = E(0.5d)

ΔV = 0.5Ed

ΔV = 0.5 (1500)(1.5 x 10⁻²)

ΔV = 11.25 V

<h3>Speed of the proton </h3>

U = ¹/₂mv²

U = mv²

v² = 2U/m

where;

  • m is mass of proton = 1.67 x 10⁻²⁷ kg

v² = (2 x 3.6 x 10⁻¹⁸) / ( 1.67 x 10⁻²⁷)

v² = 4.311 x 10⁹

v = √(4.311 x 10⁹)

v = 6.57 x 10⁴ m/s

Thus, the proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

The potential difference between the negative plate and a point midway between the plates is 11.25 V.

The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

Learn more about potential difference here: brainly.com/question/24142403

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