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lora16 [44]
3 years ago
13

Easy Questions! Chemistry - Please help! I give thanks

Chemistry
2 answers:
Evgen [1.6K]3 years ago
8 0
This is not chemistry but

see it is a triangular prim on it's side
V=BH
are of base times height
the base is a triangle
height is 18.5

base=1/2bh
b=8.6
h=8.4
base=1/2(8.6)(8.4)
base=36.12

V=bh
V=36.12*18.5
V=668.22

round
V=668.2 ft^3
artcher [175]3 years ago
4 0
All sides have to be exact
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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.
Sindrei [870]

The molar solubility is 7.4×10^{-3} M and the solubility is  7.4×10^{-3} g/L .

Calculation ,

The dissociation of silver bromide is given as ,

AgBr → Ag ^{+} + Br^{-}

S  

 -          S        S        

Ksp =  [Ag ^{+} ] [ Br^{-} ]  =  [S] [ S ] = S^{2}

S = √ Ksp = √ 5. 5×10^{-5} = 7.4×10^{-3}

The solubility =7.4×10^{-3} g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of AgBr is dissociates and form one mole of each  Ag ^{+} and Br^{-} ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×10^{-3} mol/L = 7.4×10^{-3} M

To learn more about molar solubility ,

brainly.com/question/16243859

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7 0
1 year ago
Please answer this question for 10 points
Dmitry_Shevchenko [17]
Is A have a nice day good luck b
4 0
3 years ago
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In the redox conversion of Ni2+ to NiO4−, the oxidation number of Ni goes from (−2, 0, +2) to (−1, +1, +7, +9). Recall that the
inessss [21]
Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. In neutral substances that contains atoms of one element the oxidation number of an atom is zero. Thus atoms in O2, Ni2, and aluminium all have oxidation number of zero.
In this case, Ni2, the oxidation number of Ni atom is zero, 
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Which of the following has kinetic energy?
shepuryov [24]

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moving arrow

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2 years ago
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How many grams are in 11.9 moles of chromirum
faust18 [17]

Answer:

Explanation:

Method 1 proportion

1 mole of chromium is 52 grams

11.9 moles = x grams

1/11.9 = 52/x                    Cross multiply

x = 11.9 * 52

x = 618.8                         grams

Now I have used an approximate mass for Chromium. The answer you get here is expected to reflect the weigth given on your periodic table Use that to get your answer. You should give a number very close to mine. Round to 3 places as in 619.

Method Two  Formula

mols = given mass / molecular mass

11.9 = given mass /  51.9961          Multiply both sides by  51.9961

11.9 *51.9961  = given mass            

given mass = 618.75

given mass = 619

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3 years ago
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