Easy Questions! Chemistry - Please help! I give thanks

Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are ac

Vitek1552 [10]

Answer:

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

Explanation:

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

6 0

3 years ago

Describe the relationship between volume and temperature of an ideal gas

kvv77 [185]

Answer:

Explanation:

Here, we want to describe the relationship between the volume and temperature of an ideal gas

This relationship is defined by Charles' law

From this law, we know that the volume of a given mass of gas is directly proportional to its temperature at a fixed pressure

What this means is that as long as the pressure remains unchanged, when the volume increases, the temperature increases, and when the volume decreases, the temperature decreases

These can be represented by the mathematical formula below:

$\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}$

8 0

1 year ago

A weak acid (ha) has a pka of 4.001. If a solution of this acid has a ph of 4.110, what percentage of the acid is not ionized? (

OverLord2011 [107]

99.9224 % of the acid is not ionized.

____HA + H₂O ⇌ A⁻ + H₃O⁺

I: ___c ________0 ____0

C: _-αc _______+αc __+αc

E: c(1-α) _______αc ___αc

pH = 4.110

[H₃O⁺] = αc = 10^(-4.110) mol/L = 7.76 × 10⁻⁵ mol/L

α = 7.76 × 10⁻⁵

1 – α = 1 - 7.76 × 10⁻⁵ = 0.999 224 = 99.9224 %

7 0

3 years ago

4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.

Elodia [21]

Answer:

$Y=48.6\%$

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

$2Cu+O_2\rightarrow 2CuO$

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

$m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO} =0.078gCuO$

Therefore, the percent yield is:

$Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%$

Best regards.

6 0

3 years ago

An unknown compound displays singlets at δ 2.1 ppm and 2.56 ppm in the ratio of 3:2. what is the structure of the compound?

olasank [31]

1) As can be seen from any 1H NMR chemical shift ppm tables, hydrogens which have δ values from 2ppm to 2.3ppm are hydrogens from carbon which is bonded to a carbonyl group. From this, we can conclude that our hydrogens belong to the type, but from 2 different alkyl groups because of 2 different signals.

2) So, one alkyl group is CH3 and second one can be CH or CH2.

3) If we know that ratio between two types of hydrogens is 3:2, it can be concluded that second alkyl group is CH2.

4) Finally, we don't have any other signals and it indicates that part of the compound which continues on CH2 is exactly the same as the first part.

The ratio remains the same, 3:2 ie 6:4

7 0

3 years ago