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3 years ago

Which of these energy resources does NOT pollute when used?

Chemistry

1 answer:

kondaur [170]3 years ago

5 0

Among all of them,I think the one that doesn’t pollute the environment is Hydroelectric

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Which two letters has the most kinetic energy? W X Y Z

hichkok12 [17]

Answer:

x and y

Explanation:

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2 years ago

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__________ often cause overactive eye movement. A. Stimulants B. Depressants C. Barbiturates D. None of the above

jeka57 [31]

Stimulants often cause overactive eye movement

Ans (A)

Stimulants are a class of psychoactive drugs that increase the brain activity. They work by acting on the central nervous system and increase the level of mental alertness and impart heightened cognitive functions. Stimulants like nicotine and cocaine cause overactive eye movement.

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3 years ago

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Someone plss help me!!!

NikAS [45]

Answer:

d. Cl2

sorry if I'm wrong

Cl2, as shown in the picture should have electrons in both the atoms but, in the question, the electrons are only in one of the atoms.

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2 years ago

Which of the following units is best when measuring the length of an object?

podryga [215]

Answer:metres

Explanation:It would be best to measure the length of an object in metric system such as millimeter, centimeter, mere etc..

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3 years ago

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For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80

Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

$A\rightleftharpoons B$

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

$K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%} =0.25$

Thus, by recalling the Van't Hoff's equation, we can write:

$ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )$

Hence, we solve for the enthalpy change as follows:

$\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }$

Finally, we plug in the numbers to obtain:

$\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}$

Learn more:

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2 years ago