Never mind, I did the problem wrong, I deeply apologize.
Answer:
-290KJ/mol
Explanation:
ΔHrxn = ΔHproduct - ΔHreactant
ΔHrxn= 4ΔHH3PO4 - {6ΔHH2O + ΔHP4O10}
ΔHrxn = 4(-1279) - [6(-286) - 3110]
= -5116 -(-1716-3110)
= -5116-(-4826)
= -5116 + 4826 = -290KJ/mol
Hello!
The balanced equation for the
neutralization of KOH is the following:
HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)
To calculate the
volume of HCl required, we can apply the following equation:

So, the required volume of HCl is
541,54 mLHave a nice day!