You have a 7-m-long copper wire. You want to make an N-turn current loop that generates a 6.582 mT magnetic field at the center
when the current is 4.092 A. You must use the entire wire. What will be the diameter of your coil?
1 answer:
Answer:
0.042 m
Explanation:
L = length of the copper wire = 7 m
N = Number of turns in the current loop
B = magnetic field at the center = 0.006582 T
i = current flowing through the wire = 4.092 A
r = radius of the coil
length of the copper wire is given as
L = 2πrN
7 = 2πrN
rN = 1.115
eq-1
Magnetic field at the center of the coil is given


r = 0.021 m
diameter is given as
d = 2r
d = 2 (0.021)
d = 0.042 m
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