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3 years ago

What is (a) the x component and (b) the y component of the net electric field at the square's center

Physics

1 answer:

Sav [38]3 years ago

8 0

Answer:

What is (a) the x component and (b) the y component of the net electric field at the square's center

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What is conserved in an inelastic collision?

cupoosta [38]

"Energy and Momentum" is always conserved in an inelastic condition

Hope this helps!

4 0

3 years ago

a ray of light strikes a plane mirror at an angle of 53 degrees to the normal. what is the angle of reflection?

Alexxx [7]

So for an incident rag from vacuum to a medium with n=1.6, and an incident angle of 53 degrees, the the angle of refraction will be .

4 0

3 years ago

20 POINTS! PLZ HELP ME. :-)

VladimirAG [237]

Answer:

Explanation:

Because both the elements are non-metals

3 0

3 years ago

A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse

NISA [10]

Answer:

The time interval is $t = 5.48 *10^{-3} \ s$

Explanation:

From the question we are told that

The length of the string is $l = 3.00 \ m$

The mass of the string is $m = 5.00 \ g = 5.0 *10^{-3}\ kg$

The tension on the string is $T = 500 \ N$

The velocity of the pulse is mathematically represented as

$v = \sqrt{ \frac{T}{\mu } }$

Where $\mu$ is the linear density which is mathematically evaluated as

$\mu = \frac{m}{l}$

substituting values

$\mu = \frac{5.0 *10^{-3}}{3}$

$\mu = 1.67 *10^{-3} \ kg /m$

Thus

$v = \sqrt{\frac{500}{1.67 *10^{-3}} }$

$v = 547.7 m/s$

The time taken is evaluated as

$t = \frac{d}{v}$

substituting values

$t = \frac{3}{547.7}$

$t = 5.48 *10^{-3} \ s$

5 0

4 years ago

Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter 0.8

guapka [62]

Hi, thank you for posting your question here at Brainly.

This problem could be solved using this equation:

Diffraction limit = 1.22*wavelength/diameter

diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m

Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625

6 0

3 years ago