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coldgirl [10]
2 years ago
11

Gold has always been a highly prized metal, widely used from the beginning of history as a store of value. It doesn\'t rust like

iron and doesn\'t become tarnished like silver. It is so chemically inert that it won\'t react even with the strongest concentrated acids. But it can be dissolved in aqua regia – a fresh-prepared mixture of concentrated HNO3 and HCl (1:3). When Germany invaded Denmark in World War II, the Hungarian chemist George de Hevesy dissolved the gold Nobel Prizes of Max von Laue and James Franck in aqua regia to prevent the Nazis from stealing them. He placed the jar with the solution on a shelf in his laboratory, and after the war, precipitated the gold out of the acid and returned it to the Royal Swedish Academy of Sciences and the Nobel Foundation who recast the medals and again presented them to Laue and Franck. The unbalanced equation for the reaction of gold with aqua regia is given below. Add the stoichiometric coefficients to the equation to balance it.Au(s)+HNO3(aq)+HCl(aq)--> HAUCl4(aq)+NO2(g)+H20(l)What's the function of HCL?
Chemistry
1 answer:
Alecsey [184]2 years ago
4 0

Answer:

1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)

The function of HCl is oxidize the gold.

Explanation:

It is possible to balance the reaction seeing each compound as a variable and take an equation for each atom, thus:

Au(s) + HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)

a       +       b         +      c      =        d            +    e       +    f

Au: a = d <em>(1)</em>

H: b + c = d + 2f <em>(2)</em>

N: b = e <em>(3)</em>

O: 3b = 2e + f <em>(4)</em>

Cl = c = 4d <em>(5)</em>

Assuming <em><u>a = 1</u></em>:

<em><u>1 = d</u></em> <em>(1)</em>

<u><em>c = 4</em></u> <em>(5)</em>

b + 3 = 2f <em>(2)</em>

3b = 2e + f <em>(4)</em>

As b = e:

b = f <em>(4)</em>

<em><u>f = 3</u></em>; <em><u>b = 3</u></em>; <em><u>e = 3</u></em>

Thus, balanced reaction is:

1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)

<em>The function of HCl is oxidize the gold</em> that before reaction is Au⁰ and afte ris Au⁺³

I hope it helps!

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Olegator [25]

Answer:

Eg:Salt...Essentially, water moves across a cell membrane to try to equalize the salinity or concentration of salt on both sides of the membrane. If you add enough salt, too much water will be removed from a cell for it to stay alive or reproduce. A high concentration of salt kills organisms that decay food and cause disease.

Explanation:

8 0
3 years ago
Your job is to determine the concentration of ammonia in a commercial window cleaner. In the titration of a 25.0 mL sample of th
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Answer:

The initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      .....(1)

Molarity of HCl solution = 0.164 M

Volume of solution = 23.8 mL = 0.0238 L    (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

0.164M=\frac{\text{Moles of HCl}}{0.0238L}\\\\\text{Moles of HCl}=(0.146mol/L\times 0.0238L)=0.0035mol

The chemical equation for the reaction of ammonia and HCl follows:

NH_3+HCl\rightarrow NH_4^++Cl^-

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of ammonia

So, 0.0035 moles of HCl will react with = \frac{1}{1}\times 0.0035=0.0035mol of ammonia

  • Calculating the initial concentration of ammonia by using equation 1:

Moles of ammonia = 0.0035 moles

Volume of solution = 25 mL = 0.025 L

Putting values in equation 1, we get:

\text{Initial concentration of ammonia}=\frac{0.0035mol}{0.025L}=0.14M

By Stoichiometry of the reaction:

1 mole of ammonia produces 1 mole of ammonium ion

So, 0.0035 moles of ammonia will react with = \frac{1}{1}\times 0.0035=0.0035mol of ammonium ion

  • Calculating the concentration of ammonium ion by using equation 1:

Moles of ammonium ion = 0.0035 moles

Volume of solution = [23.8 + 25] mL = 48.8 mL = 0.0488 L

Putting values in equation 1, we get:

\text{Molarity of ammonium ion}=\frac{0.0035mol}{0.0488L}=0.072M

  • To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

K_w=K_b\times K_a

where,

K_w = Ionic product of water = 10^{-14}

K_a = Acid dissociation constant

K_b = Base dissociation constant = 1.8\times 10^{-5}

10^{-14}=1.8\times 10^{-5}\times K_a\\\\K_a=\frac{10^{-14}}{1.8\times 10^{-5}}=5.55\times 10^{-10}

The chemical equation for the dissociation of ammonium ion follows:

NH_4^+\rightarrow NH_3+H^+

The expression of K_a for above equation follows:

K_a=\frac{[NH_3][H^+]}{[NH_4^+]}

We know that:

[NH_3]=[H^+]=x

[NH_4^+]=0.072M

Putting values in above expression, we get:

5.55\times 10^{-10}=\frac{x\times x}{0.072}\\\\x=6.32\times 10^{-6}M

To calculate the pH concentration, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=6.32\times 10^{--6}M

pH=-\log (6.32\times 10^{-6})\\\\pH=5.20

Hence, the initial concentration of ammonia is 0.14 M and the pH of the solution at equivalence point is 5.20

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3 years ago
How many moles of oxygen gas occupy 67.2 L of volume at STP?<br> A 0.333<br> B 3.00<br> C 1.00
posledela

Answer:

I would say b hope this helps

Explanation:

have a good day btw i had this question before:D

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for the reaction HCI+NaOH➡️NaCi+H2O, how many moles of hydrochloric acid are required to produce 150 g. of water?
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Answer: 8.33 mol of HCl (Hydrochloric Acid)

Explanation:

150 g H2O  x __1 mol__ x __1 mol HCl__  =  8.33 mol of HCl

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