Answer:
The molar solubility of SrCO3 will be lower in 0.10 M 0 M Sr(NO3)2 because of Sr2+
Explanation:
The question reflects the phenomenon known in chemistry as common ion effect. Common ion effect refers to the decreased solubility of a solid in a solution that contains an ion in common with the solute.
In the case of our example here, both strontium carbonate and strontium nitrate possess the strontium II ion in common. The presence of this ion in strontium nitrate will decrease the solubility of strontium carbonate in accordance with Le Chateliers principle. Hence the answer.
Answer:
12.875
Explanation:
Balanced equation of the reaction:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
mole of acid = mole of base
75 × 0.150 = volume of base needed × 0.3
volume of base needed = 37.5 ml
excess OH = 0.3 × 37.5 ml / 150 ml where total volume = 75 ml + 75 ml = 150 ml
excess OH = 0.075 M
pOH = - log (OH⁻) = - log (0.075 M) = 1.125
pH + pOH = 14
pH = 14 - pOH = 14 - 1.125 = 12.875
My sample would be 4000 years old because on my graph, I had about 9 Virtualium left at trial 4 so I am guessing that it would be 4000 years old.
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