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3 years ago

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A spatially challenged goldfish swims along the x-axis only. Its initial position is 7.8 m. After swimming back and forth a whil

e, it finds itself at the position 4.4 m. Calculate the fish’s displacement (including its sign).

1 answer:

Nostrana [21]3 years ago

6 0

Answer:

-3.4 m

Explanation:

The displacement is the difference between the final position and the initial position:

4.4 m - 7.8 m = -3.4 m

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$1 \times 10^{-10.1} \mathrm{Wm}^{-2}$ is the intensity of the sound.

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Where,

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$I_{0}$ = Standard Intensity of sound of 60 decibels = $1 \times 10^{-12} \mathrm{Wm}^{-2}$

So for 19 decibels, determine I as follows,

$19 d B=(10 d B) \times \log _{10}\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)$

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When log goes to other side, express in 10 to the power of that side value,

$\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)=10^{1.9}$

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1. Vpa = 180m/s. @ 0 deg.
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